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lara [203]
3 years ago
7

** will mark you brainliest **

Chemistry
2 answers:
insens350 [35]3 years ago
8 0

Its B. Using 150 cm3 of hydrogen peroxide

Andrei [34K]3 years ago
7 0

The answer is B because when you calculate it you will get the same amount of hydrogen peroxide.

Good luck,!

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What best describes the energy changes associated with evaporation and boiling
erik [133]

Answer:The statement 'atoms gain energy during evaporation and boiling' BEST describes the energy changes associated with evaporation and boiling.

In a given substance (e.g., water), atoms gain energy when they obtain kinetic energy, i.e. when they gain movement.

Evaporation refers to the physical process where a liquid is converted to a gas (in this case, water).

These processes (evaporation and boiling) increase the kinetic energy of water molecules to the detriment of the potential energy.

In conclusion, the statement 'atoms gain energy during evaporation and boiling' BEST describes the energy changes associated with evaporation and boiling.

4 0
2 years ago
A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
zysi [14]
            <span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)

grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
7 0
3 years ago
Read 2 more answers
Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou
lesya [120]
First, let's compute the number of moles in the system assuming ideal gas behavior. 

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>
3 0
4 years ago
Both 1,2−dihydronaphthalene and 1,4−dihydronaphthalene may be selectively hydrogenated to 1,2,3,4−tetrahydronaphthalene. One of
pochemuha

Answer:

1,4-dihydro = 113 kJ·mol⁻¹

1,2-dihydro = 101 kJ·mol⁻¹

Explanation:

In 1,4-dihydronaphthalene, the 2,3-double bond is isolated from the benzene ring.

In 1,2-dihydronaphthalene, the 3,4-double bond is conjugated with the benzene ring.

Thus, 1,2-dihydronaphthalene is partially stabilized by resonance interactions between the ring and the double bond (think, styrene).

1,2-Dihydronaphthalene is at a lower energy level because of this stabilization.

The heat of hydrogenation of 1,2-dihydronaphthalene is therefore less than that of the 1,4-isomer when each is hydrogenated to the common product, 1,2,3,4-tetrahydronaphthalene.

8 0
3 years ago
For every 1.0 mole of glycine in the sample, how many molecules of methionine are present? (for help performing calculations wit
krok68 [10]

1.08 X 10^21 molecules

3 0
3 years ago
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