Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Easy 31 feet per second take 279 and divide it by 9 and you get 31
Answer:
A. 49
Step-by-step explanation:
The average rate of change for the interval ranging from x = 3 to x = 5 for the given function represented in the table above can be calculated using:
x2 = 5
x1 = 3
f(x2) = f(5) = 125
f(x1) = f(3) = 27
Thus,
Average rate of change = 49
Average rate of change of the given table values representing an exponential function is A. 49.
Bisected means cut in half. half of 62 is ,31
