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andrew-mc [135]
2 years ago
11

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 49.0 and 54.

0 minutes. Find the probability that a given class period runs between 50.75 and 51.75 minutes.
Find the probability of selecting a class that runs between and minutes.
Mathematics
1 answer:
Pie2 years ago
8 0

Answer:

0.2

Step-by-step explanation:

Write a proportion.

(54.0 − 49.0) / 1 = (51.75 − 50.75) / x

5 = 1 / x

x = 0.2

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Which of the following statements are true?
bezimeni [28]

Answer:

A, B, and C are all true.

Step-by-step explanation:

A. 6 is neither a perfect square nor a perfect cube.   True

B. 16 is a perfect square.   True 4^{2}

C. 27 is a perfect cube.   True 3^{3}

OD. 1,331 is both a perfect square and a perfect cube.   False

E. 9 is a perfect cube.  False

6 0
3 years ago
Is 43 a composite number
kobusy [5.1K]

Answer:

43 is not a composite number

Step-by-step explanation:

43 is a prime number

6 0
2 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
3 years ago
Simplify this equation <br> Thanks a lot!!!
den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

4 0
3 years ago
Please answer this question
Gelneren [198K]
A=2(LW+LH+WH)

A=2((7/8)(1/3)+(7/8)(2/5)+(1/3)(2/5))

A=2(7/24+14/40+2/15)

A=14/24+28/40+4/15

A=7/14+7/10+4/15  210

A=(105+147+56)/210

A=308/210

A=(210+98)/210

A=1 98/210

A=1 7/15
8 0
2 years ago
Read 2 more answers
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