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Galina-37 [17]
3 years ago
11

If an olivine liquid containing 50 weight % forsterite (Fig. 8.9) were cooled slowly until it was 50% crystallized, and then all

of the crystals were separated from the liquid (perhaps as a result of crystal settling) what composition would the remaining liquid have (use the lever rule)?
Chemistry
1 answer:
erik [133]3 years ago
5 0

Answer:

0.35 weight fraction is liquid Forsterite and 0.65 weight fraction is liquid Fayolite

Explanation:

The lever rule is typically used to calculate the weight fractions of phases in a binary equilibrium phase diagram. It is also used in the estimation of the fraction of solid and liquid phases for a specific binary composition and temperature condition existing between the solid and liquid lines. Therefore, using the Figure. 8.9 and the use of lever rule, the composition of the remaining liquid would be 0.35 weight fraction of liquid Forsterite and 0.65 weight fraction of liquid Fayolite.

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Need help !!!!! Stuck asap
Step2247 [10]
<h2>Hello!</h2>

The answer is:

Hence, the new pressure will be 2.07 atm.

P_{2}=2.07atm

<h2>Why?</h2>

Since we know that the gas is inside of a rigid container, meaning that the volume will be kept constant, we can solve the problem using the Gay-Lussac's Law.

The the Gay-Lussac's Law establishes that when an ideal gas is kept at the same volume, the pressure and the temperature will be proportional.

We need to pay special attention when we are working with the Gay-Lussac's Law since its equaitons works with absolute temperatures (Kelvin ), so, if we are working with relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert the temperatures to Kelvin.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°)+273

So, we have the Gay-Lussac's equation:

\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}

Also, we are given the following information:

T_{1}=30\° \\P_{1}=2atm\\T_{2}=40\°

Therefore, converting the temperature to Kelvin, we have:

T_{1}=30C\°=30+273K=303K\\\\T_{1}=40C\°=40+273K=313K\\

Now, calculating we have:

\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}

P_{2}=\frac{P_{1}}{T_{1}}*T_{2}\\\\P_{2}=\frac{2atm}{303K}*313K=2.07atm

Hence, the new pressure will be 2.07 atm.

P_{2}=2.07atm

Have a nice day!

4 0
4 years ago
What is the representative particle for an element?
xz_007 [3.2K]

Answer:

The representative particle for an element is AN ATOM.

Explanation:

Representative particle of a substance refers to the smallest unit of that substance, which can not be broken down into smaller particles. The representative particles of an element is an atom, because each element is made up of atoms, which are the smallest unit of that element; they can not be broken down further.

A representative particle is chemically identical with the parent element and will have all the properties of the parent element.  

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3 years ago
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Karolina [17]

Answer:

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Explanation:

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In NaI, Na is a metal and I a nonmetal, so they form an ionic bond, where Na loses an electron to form Na⁺ and I gains an electron to form I⁻.  Anions and cations are attracted to each other through electrostatic forces.

Since ionic bonds are stronger than covalent bonds, more energy is required to break them in the melting process, thus having higher melting points.

All in all, NaI is the one with the highest melting point.

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