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amid [387]
2 years ago
6

In TEN complete sentences, describe how the LAW OF CONSERVATION applies to the stuff YOU OWN. For example: In real life, can new

XBOXs be magically created, or garbage magically destroyed? Why? You are made up of recycled atoms. Where did these atoms come from? *
Chemistry
1 answer:
satela [25.4K]2 years ago
6 0

Answer:

Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and type of atoms after the chemical change as were present before the chemical change.

Explanation:

The atoms that make up your body were produced inside a star and have ... I read once that atoms get recycled so much through the planet that each of ... from William Shakespeare, but I do know this: All of us come from stars. ... If you have gold fillings in your teeth, those atoms came from a star explosion.

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What is the diameter of Neptune in standard notation
Misha Larkins [42]

Answer:

The diameter of Neptune is approximately 49,500 km. This makes Neptune the 4th largest planet in the Solar System, after Jupiter, Saturn and Uranus.

7 0
3 years ago
Given the three equations below, what is the heat of reaction for the production of glucose, C6H12O6, as described by this equat
UkoKoshka [18]

Answer:

- 1273.02 kJ.

Explanation:

This problem can be solved using Hess's Law.

Hess's Law states that <em>regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes. This law is a manifestation that enthalpy is a state function.</em>

  • We should modify the given 3 equations to obtain the proposed reaction:

<em>6C(s) + 6H₂(g) + 3O₂(g) → C₆H₁₂O₆(s),</em>

<em></em>

  • We should multiply the first equation by (6) and also multiply its ΔH by (6):

6C(s) + 6O₂(g) → 6CO₂(g), ∆H₁ = (6)(–393.51 kJ) = - 2361.06 kJ,

  • Also, we should multiply the second equation and its ΔH by (6):

6H₂(g) + 3O₂(g) → 6H₂O(l), ∆H₂ = (6)(–285.83 kJ) = - 1714.98 kJ.

  • Finally, we should reverse the first equation and multiply its ΔH by (- 1):

6CO₂(g) + H₂O(l) → C₆H₁₂O₆(s) + 6O₂(g), ∆H₃ = (-1)(–2803.02 kJ) = 2803.02 kJ.

  • By summing the three equations, we cam get the proposed reaction:

<em>6C(s) + 6H₂(g) + 3O₂(g) → C₆H₁₂O₆(s),</em>

<em></em>

  • And to get the heat of reaction for the production of glucose, we can sum the values of the three ∆H:

<em>∆Hrxn = ∆H₁ + ∆H₂ + ∆H₃ =</em> (- 2361.06 kJ) + (- 1714.98 kJ) + (2803.02 kJ) = <em>- 1273.02 kJ.</em>

6 0
2 years ago
Read 2 more answers
The absorbance of a chlorophyll a standard solution in ethanol (density = 0.785 g/mL) is measured in
Dmitry_Shevchenko [17]
Let <span>A= ebc </span>
<span>     0.765 = 86,300*1.3*c </span>
<span>
Solve for c = approximately 7E-6 Molar
                  = mols/L soln. </span>
<span>g = 7E-6*893.49
   = about 0.006 g chlorophyll/L soln. </span>
<span>
1000 x 0.785 = 785 g ethanol. </span>
<span>Conc. = about 0.006g chlorophyll/785 g soln. </span>
<span>
Change that to ppm. by using formula:
(0.006/785)*1E6</span>
5 0
2 years ago
Read 2 more answers
A 1.775g sample mixture of potassium hydrogen carbonate is decomposed by heating. if the mass loss is 0.275g what is the percent
Marina86 [1]

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

  • Step 1: Write the balanced equation for the decomposition of KHCO₃.

2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)

The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.

  • Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.

In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.

0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃

  • Step 3: Calculate the mass percentage of KHCO₃ in the sample.

There are 1.25 g of KHCO₃ in the 1.775 g sample.

%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

Learn more about decomposition reactions here: brainly.com/question/14219426

7 0
2 years ago
How many atoms of hydrogens are found in 3.21 mol of<br>C3H8?​
damaskus [11]

Answer:

1.55 × 10²⁵ atoms of H  

Explanation:

3.21mol C₃H₈ × 8mol H × (6.022×10²³)

8 0
2 years ago
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