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Schach [20]
3 years ago
14

When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

f the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon, in kJ/mol?
Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer:

S A T. NV

Explanation:

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In a particular experiment at 300 ∘C, [NO2] drops from 0.0100 to 0.00800 M in 100 s. The rate of appearance of O2 for this perio
Tems11 [23]

Answer:

1\times{10}^{-5}\frac{M}{s}

Explanation:

The stoichiometry for this reaction is  

2NO_2\rightarrow2NO+O_2

The rate for this reaction can be written as  

-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}

This rate of disappearence of NO_2 can be realated to the rate of appearence of O_2 as follows  (the coefficients of each compound are defined by the stoichiometry of the reaction)

-r_{O_2}=-r_{NO_2}\times\frac{coefficient\ O_2\ }{coefficient\ NO_2}=2\times{10}^{-5}\frac{M}{s}\times\frac{1\ mole\ O_2\ }{2\ mole\ NO_2}=1\times{10}^{-5}\frac{M}{s}

6 0
4 years ago
Please respond guys I’ll give brainliest and 100 points
Contact [7]

Answer:

Name

Atomic Number

Atomic Symbol

Atomic Weight

Phase

Color

Classification

Group in Periodic Table

Group Name

Period in Periodic Table

Block in Periodic Table

Electronic Configuration

Melting Point

Boiling Point

Electronic Shell Structure

CAS Number

Neighborhood Elements

Lithium

3

Li

6.941

Solid

Silver

alkali metal

1

lithium family  

2

s

[He] 2s1

180.54 °C

1342 °C

2, 1

CAS7439-93-2

Neighborhood Elements of Lithium

Cesium

55

Cs

132.90545

Solid

Silver

alkali metal

1

lithium family  

6

s

[Xe] 6s1

28.44 °C

671 °C

2, 8, 18, 18, 8, 1

CAS7440-46-2

Neighborhood Elements of Cesium

Explanation:

4 0
3 years ago
A rock is believed to have been formed 1.25 billion years ago, as calculated by using potassium-40 dating. If the half-life of p
Leya [2.2K]

Answer:

The answer to the question is

50 % of the original amount of potassium 40 will be left after one half life or 1.25 billion years

Explanation:

To solve the question we note that the half life is the time for half of the quantity of  substance that undergoes radioactive decay to  disintegrate, thus

we have

half life of potassium 40 K₄₀ = 1.25 billion years

To support the believe tht the rock was formed 1.25 billion years ago we have

N_{(t)} =N_{(0)} (\frac{1}{2}) ^{\frac{t}{t_{\frac{1}{2} } } }

After 1.25 billion years we have

N_{(t)} =N_{(0)} (\frac{1}{2}) ^{\frac{1.25billion}{1.25 billion}  } } }  = N_{(t)} =N_{(0)} (\frac{1}{2}) ^{1 } } } =0.5 of N_{(0)} will be left or 50 % of the original amount of potassium 40 will be left

4 0
4 years ago
Explain how creativity can play a role in the construction of scientific questions and hypotheses.
ozzi
Like if you imagine making something you create a hypothesis about was to make that happen
6 0
4 years ago
Which of these is not true?
makvit [3.9K]

Answer:

C. Atoms have isotopes of an element have different numbers of protons.

Explanation:

The isotopes are the variation in the number of neutrons (neutral charge), with increases the weight of the atom, so the first one, is related to this one.

5 0
3 years ago
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