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Schach [20]
3 years ago
14

When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

f the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon, in kJ/mol?
Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer:

S A T. NV

Explanation:

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A sample of air was collected on a day when the total atmosphere pressure was
zhuklara [117]

Answer:

1. The gas law used: Dalton's law of partial pressure.

2. Pressure of nitrogen = 331 mmHg

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 592 mmHg

Pressure of Oxygen (Pₒ) = 261 mmHg

Pressure of nitrogen (Pₙ) =?

The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:

Pₜ = Pₒ + Pₙ

592 = 261 + Pₙ

Collect like terms

592 – 261 = Pₙ

331 = Pₙ

Pₙ = 331 mmHg

Therefore, the pressure of nitrogen in the sample is 331 mmHg

5 0
3 years ago
A chemical formula written above or below the yield sign indicates:
sweet-ann [11.9K]
I believe the correct answer from the choices listed above is option B. A chemical formula written above or below the yield sign indicates <span>that the substance is used as a catalyst. I am certain with this answer. Hope this helps. Have a nice day.</span>
3 0
3 years ago
Read 2 more answers
Revolver features several firing chambers located within...
Blizzard [7]

Answer:

What are the characteristics of a revolver?

Explanation:

The revolver features several firing chambers located within a revolving cylinder. The cylinder rotates as the revolver is fired, lining up each bullet mechanically.

8 0
3 years ago
2. How many moles are in 8.30 x 1023 molecules of H2O?
daser333 [38]

Answer:

<h2>1.38 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.30 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{8.30}{6.02}  \\  = 1.3787 37...

We have the final answer as

<h3>1.38 moles</h3>

Hope this helps you

8 0
3 years ago
Why are gas bubbles not always a sign of a chemical change?
Mekhanik [1.2K]

Answer: its a reaction

Explanation:

like coke its a reaction between gas and oxygen

3 0
3 years ago
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