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Schach [20]
3 years ago
14

When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

f the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon, in kJ/mol?
Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer:

S A T. NV

Explanation:

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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 J electrical energy is
Alchen [17]

B) It was transformed into 350 J of heat energy.

Explanation:

The remaining 350J of energy must have been transformed into 350J of heat energy.

A fan works by converting electrical energy into heat energy.

  • According to the third law of thermodynamics "no system is 100% efficient". The conversion of the energy from one form to another involves a lost in energy.
  • Heat is one very familiar way by which energy can be lost.
  • Some component energy is used to heat the fan in the process and it is a wasted energy.
  • Friction surfaces a heat energy in this process.

learn more:

Third law of thermodynamics brainly.com/question/3564634

#learnwithBrainly

6 0
3 years ago
Which of the following best describes the impact of glaciers upon the surface of the earth?
Ahat [919]

Answer:

D. All of the above

Explanation:

Because all of these have something to do with how glaciers are affecting the planet.

6 0
3 years ago
Omg pls help i dunno what the frick frack this is
snow_lady [41]

Answer:

1. Mass of KCl produced = 774.8 g of KCl

2. Mass of KNO₃ produced = 13.837g

3. Moles of NaOH made = 0.846 moles

4. Moles of LiCl produced = 0.846 moles

5. Moles of CO₂ produced = 207.6 moles

Explanation:

1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.

5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl

Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol

10.4 moles of KCl = 10.4 × 74.5 g

Mass of KCl produced = 774.8 g of KCl

2. Mole ratio of KNO₃ and KOH = 1:1

O.137 moles of KOH will produce 0.137 moles of KNO₃

Molar mass of KNO₃ = 101 g/mol

Mass of KNO₃ produced = 0.137 × 101 g = 13.837g

3. Molar mas of Ca(OH)₂ = 74.0 g

Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂

Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1

Moles of NaOH made = 2 × 0.423 = 0.846 moles

4. Molar mass of MgCl₂ = 95.0 g

Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles

From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2

Moles of LiCl produced = 2 × 0.423 = 0.846 moles

5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂

34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂

Moles of CO₂ produced = 207.6 moles

4 0
3 years ago
Oxygen gas is collected at a pressure of 123 kPa in a container which has a volume of 10.0L. What temperature must be maintained
Morgarella [4.7K]
Given:

P = 123 kPa
V = 10.0 L
n = 0.500 moles
T = ?

Assume that the gas ideally, thus, we can use the ideal gas equation:

PV = nRT

where R = 0.0821 L atm/mol K

123 kPa * 1 atm/101.325 kPa * 10.0 L = 0.500 moles * 0.0821 Latm/molK * T

solve for T 

T = 295.72 K<span />
5 0
3 years ago
Read 2 more answers
What is a common effect of warm ocean currents on nearby coastlines?
Anton [14]
D Im pretty sure. D
7 0
3 years ago
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