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faltersainse [42]
3 years ago
9

Which pair of sentences is describing the same velocity? A car is parked. A car is moving in circles. A bus drives 40 miles per

hour north. A truck drives 50 miles per hour north. A boy walks east at 6 kilometers per hour. A girl walks west at the same speed as the boy. Valerie rides her bike south at 8 kilometers per hour. Owen jogs south at 8 kilometers per hour.
Physics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
The bus and the truck have the same velocity.

Also, Valerie and Owen have the same velocity.
Phoenix [80]3 years ago
7 0

Velocity is a vector, so it contains two pieces of information:

- a magnitude, which is given by the speed

- a direction

Two objects, in order to have same velocity, should have both same speed and same direction. In this problem, only the following pair of sentences describe people with same velocity:

Valerie rides her bike south at 8 kilometers per hour.

Owen jogs south at 8 kilometers per hour.

In fact, both Valerie and Owen are moving at same speed (8 km per hour) in the same direction (south), so they have same velocity.

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A cannonball is fired vertically upwards at 100.0 m/s a) How long will it take to return to the cannon? b) what is it's maximum
V125BC [204]
Answer:
a) 20s
b) 500m

Explanation:
Given the initial velocity = 100 m/s, acceleration = -10m/s^2 (since it is moving up, acceleration is negative), and at the maximum height, the ball is not moving so final velocity = 0 m/s.

To find time, we apply the UARM formula:

v final = (a x t) + v initial

Replacing the values gives us:

0 = (-10 x t) + 100

-100 = -10t

t = 10s

It takes 10s for the the ball to reach its max height, but it must also go down so it takes 2 trips, once going up and then another one going down, both of which take the same time to occur

So 10s going up and another 10s going down:

10x2 = 20s

b) Now that we have v final = 0, v initial = 100, a = -10, t = 10s (10s because maximum displacement means the displacement from the ground to the max height) we can easily find the displacement by applying the second formula of UARM:

Δy = (1/2)(a)(t^2) + (v initial)(t)

Replacing the values gives us:

Δy = (1/2)(-10)(10^2) + (100)(10)

= (-5)(100) + 1000

= -500 + 1000

= 500 m

Hope this helps, brainliest would be appreciated :)
7 0
2 years ago
g An astronaut must journey to a distant planet, which is 189 light-years from Earth. What speed will be necessary if the astron
Butoxors [25]

Answer:

The value is v  =  2.999 *10^{8} \  m/s

Explanation:

From the question we are told that

   The time taken to travel to the planet from earth is t = 189 \ light-years

    The  time to be spent on the ship is  t_{s} =  12 \  years

Generally speed can be obtained using the mathematical relation represented below

       t_s  =  2 * t *  \sqrt{1 -  \frac{v^2}{c^2 } }

The 2 in the equation show that the trip is a round trip i.e going and coming back

=>    12 =  2 * 189 *  \sqrt{1 -  \frac{v^2}{(3.0*10^{8})^2 } }

=>     v  =  2.999 *10^{8} \  m/s

5 0
3 years ago
Lifting a box off the floor is an example of what type of force?
s2008m [1.1K]
Gravitational I think would be the answer, Hope this helps!
8 0
2 years ago
Read 2 more answers
Which part of an atom is mostly empty space?
Veronika [31]

Answer:

The electron cloud is mostly empty space

7 0
3 years ago
Two cars cover the same distance in a straight line. Car a covers the distance at a constant velocity. Car b starts from rest an
Artyom0805 [142]

a) For the motion of car with uniform velocity we have , s = ut+\frac{1}{2}at^2, where s is the displacement, u is the initial velocity, t is the time taken a is the acceleration.

In this case s = 520 m, t = 223 seconds, a =0 m/s^2

Substituting

       520 = u*223\\ \\u = 2.33 m/s

 The constant velocity of car a = 2.33 m/s

b) We have s = ut+\frac{1}{2} at^2

s = 520 m, t = 223 seconds, u =0 m/s

Substituting

      520 = 0*223+\frac{1}{2} *a*223^2\\ \\ a = 0.0209 m/s^2

Now we have v = u+at, where v is the final velocity

Substituting

        v = 0+0.0209*223 = 4.66 m/s

So final velocity of car b = 4.66 m/s

c) Acceleration = 0.0209 m/s^2

7 0
3 years ago
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