The particle's acceleration is 5.1 m/s²
<h3>
What is Acceleration ?</h3>
Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²
Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s
The given parameters are;
Acceleration a = ΔV ÷ ΔT
a = (2.35 + 8.72) / (5.59 - 3.42)
a = 11.07 / 2.17
a = 5.1 m/s²
Therefore, the particle's acceleration is 5.1 m/s²
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TheThe relative velocity of Deigo will be 27km/h .
<h3>What is relative Velocity? </h3>
The relative velocity is the velocity of an object with respect to another observer. It is the time rate of relative position of one object with respect to another object .
Vab = Va-Vb
Where a is object and b is observer .
We have given here the velocity of ball 20km/ h
and the another velocity is 7km/ h
Let us assume that Diego is also moving in the direction where ball is moving so the relative velocity will be
V = 20+7=27km/ h
When both observer and object is moving in same direction than there sum of velocity will be relative velocity ,if they are moving opposite than subtraction.
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Answer:
v₂ = 7/ (0.5)= 14 m/s
Explanation:
Flow rate of the fluid
Flow rate is the amount of fluid that circulates through a section of the pipeline (pipe, pipeline, river, canal, ...) per unit of time.
The formula for calculated the flow rate is:
Q= v*A Formula (1)
Where :
Q is the Flow rate (m³/s)
A is the cross sectional area of a section of the pipe (m²)
v is the speed of the fluid in that section (m/s)
Equation of continuity
The volume flow rate Q for an incompressible fluid at any point along a pipe is the same as the volume flow rate at any other point along a pipe:
Q₁= Q₂
Data
A₁ = 2m² : cross sectional area 1
v₁ = 3.5 m/s : fluid speed through A₁
A₂ = 0.5 m² : cross sectional area 2
Calculation of the fluid speed through A₂
We aply the equation of continuity:
Q₁= Q₂
We aply the equation of Formula (1):
v₁*A₁= v₂*A₂
We replace data
(3.5)*(2)= v₂*(0.5)
7 = v₂*(0.5)
v₂ = 7/ (0.5)
v₂ = 14 m/s
20m away
the dog was 60m away from. you subtract 40m since it is 10m/s x 4 seconds
You do 1000 divide it by 10 which equals 100 W