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sladkih [1.3K]
3 years ago
14

Which of the following best describes the use of a renewable resource? (2 points) Most power plants burn fossil fuels to generat

e electricity for use in homes, offices, and other buildings. There are areas in California that use the heat from deep in the Earth to generate electricity. Propane is a product you might use to barbeque; it comes from natural gas and processing oil. We use gasoline to power our cars to get to work and school each day.
Physics
1 answer:
kolbaska11 [484]3 years ago
5 0

Which of the following best describes the use of a renewable resource?

Answer:

There are areas in California that use the heat from deep in the Earth to generate electricity.

Explanation:

It comes from the earth itself and we use a lot of things that comes from the earth and deep within it.

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Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the Earth’s m
insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

F_{mag}= BIL

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: F_{mag}  is a direct adaptation of the vector relation F=q \times V \times B</em>

From Newton's second law we know that the relation of Strength and weight is determined as

F_g = mg

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

F_{mag} = F_g

BIL = mg

Our values are given as,

Diameter (d) = 1.0mm = 1*10^{-3}m

Radius (r) = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m

Magnetic Field (B) = 5.0*10^{-5} T

From the relationship of density another way of expressing mass would be

\rho = \frac{m}{V} \rightarrow m = \rho V

At the same time the volume ratio for a cylinder (the shape of the wire) would be

V = \pi r^2 L \rightarrow L =Length, r= Radius

Replacing this two expression at our first equation we have that:

BIL = mg

BIL = ( \rho V)g

BIL = ( \rho \pi r^2 L)g

Re-arrange to find I

I = \frac{( \rho \pi r^2 L)g}{BL}

I = \frac{( \rho \pi r^2 )g}{B}

We have for definition that the Density of copper is 8.9*10^3 Kg/m^3, gravity acceleration is 9.8m/s^2 and the values of magnetic field (B) and the radius were previously given, then:

I = \frac{( (8.9*10^3 ) \pi (0.5*10^{-3})^2 )(9.8)}{5.0*10^{-5}}

I = 1370.05A

The current is too high to be transported which would make the case not feasible.

8 0
3 years ago
Please Help! ASAP!
posledela

Answer:

C and D

Explanation:

Its possible to use telescopes during the day time.

Gamma rays were found on earth's atmosphere.

8 0
3 years ago
Our data for how much force is needed can be qualitative. This means we don’t have to know exact values for the force in Newtons
kirill [66]

Answer:

For macroscopic objects, we use units such as grams and kilograms to state their masses, but. There will not be much error if you estimate the mass of an atom by simply. to what we did for our hypothetical example, but the percentages are different: Add two atomic masses of carbon and six atomic masses of hydrogen:

Explanation:

8 0
3 years ago
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If θ=0rad
wlad13 [49]

Answer:

π

Explanation:

ok that is the answer ok

4 0
2 years ago
The box as shown above is moving at a constant velocity . True or false
STatiana [176]
True because on side is heavier than the other
8 0
3 years ago
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