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german
3 years ago
15

Find the domain and range of the following functions:

Mathematics
1 answer:
never [62]3 years ago
4 0

Answer:

please provide awnser options

Step-by-step explanation:

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A 5-pack of popsicles costs $0.95. What is the unit price?
Rainbow [258]
Unit price - price of one
0.95/5= 0.19p
hope this helps
4 0
3 years ago
Read 2 more answers
Five-thirds divided by one-third Step 1: Show the dividend Five-thirds in a fraction bar. Step 2: Below the dividend, show the d
Kisachek [45]

Answer: the answer 5

Step-by-step explanation: it is 5

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2 years ago
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The carnival is in town for 21 days. How many weeks is the carnival in town?(There are 7 days in 1 week.) Write and equation,and
Elza [17]

Answer:

egn= 7x=y

where x= weeks no.

y= days

atq...x= 3

4 0
3 years ago
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors
zhuklara [117]
<h3>Answer: A) 1</h3>

=========================

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

7 0
3 years ago
The town of Madison has a population of 25{,}00025,00025, comma, 000. The population is increasing by a factor of 1.121.121, poi
cestrela7 [59]

Answer:

P(t)=25,000(1.12)^t

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

P(t)=a(b)^t

where

P(t) is the population in Madison

t is the number of years

a is the initial value

b is the factor of growth

we have

a=25,000\ people\\b=1.12

substitute

P(t)=25,000(1.12)^t

3 0
3 years ago
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