In the equation w=fd cos 0, what is the angle 0?
1 answer:
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Answer:
v = 66.7 m/s
Explanation:
Given that,
The length of steel cable, L = 600 m
Diameter = 1.2 cm
It is observed that it took 18 s for the pulse to return.
The time taken to cover 600 m will be :
t = T/2
t = 9 s
Let v be the of the pulse. We know that,
So, the speed of the pulse is equal to 66.7 m/s.
Answer: the distance between him and his friend is 218.39 feet
Explanation:
Given the data in the question;
FROM IMAGE A;
distance travelled in minute and a half
⇒ (60 + 30)sec × 4ft/sec = 360 fts
FROM IMAGE B
tan35°= h/x --- equ 1
and tan36° = h/(360 - x), so h = (360 - x)tan36°
we substitute value of h into euq 1
tan35° = (360 - x)tan36°/x
xtan35° = (360 - x)tan36°
0.7002x = 261.5553 - 0.7265x
0.7002x + 0.7265x = 261.5553
1.4267x = 261.5553
x = 183.32 feet
so
360 - x ⇒ ( 360 - 183.32) = 176.68
FROM IMAGE C
Let the distance between them be d
so
cos36° = 176.68 / d
dcos36° = 176.68
d = 176.68 / 0.809
d = 218.39 feet
Therefore the distance between him and his friend is 218.39 feet
