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vladimir1956 [14]
4 years ago
5

In the equation w=fd cos 0, what is the angle 0?

Physics
1 answer:
maria [59]4 years ago
4 0
Then it is 0. Hope that helps
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A ball of 0.1kg is thrown straight up into the air with
Contact [7]

a) The momentum of the ball at the maximum height is zero

b) The momentum of the ball at halfway is 1.06 kg m/s

Explanation:

a)

There is only one force acting on the ball during its motion: the force of gravity, acting downward. As a result, the ball hasa constant acceleration downward (g=9.8 m/s^2, acceleration of gravity), and therefore it is in free fall motion.

This means that the velocity of the ball is given by the equation:

v=u-gt

where

v is the velocity at time t

u = 15 m/s is the initial velocity

g=9.8 m/s^2

As we see from the equation, the term -gt is negative: this means that as the ball goes higher and higher, its velocity decreases. The point of maximum height is reached when the velocity has become zero (after that point, the velocity changes direction and points downward), so when

v=0

The momentum of the ball at any point is given by

p=mv

where m = 0.1 kg is its mass. Therefore, at the maximum height, since v=0, the momentum is also zero:

p=0

b)

We can use the following suvat equation to find the maximum height reached by the ball:

v^2-u^2=2as

where

v = 0 is the velocity at the point of maximum height

u = 15 m/s is the initial velocity

a=-g=-9.8 m/s^2 is the acceleration (downward)

s is the vertical displacement (the maximum height)

Solving for s,

s=\frac{v^2-u^2}{2a}=\frac{0-(15)^2}{2(-9.8)}=11.48 m

This means that the ball is halfway when its height is

h'=\frac{s}{2}=\frac{11.48}{2}=5.74 m

We can find the velocity of the ball v' when it is at h' by using again the same equation:

v'^2-u^2=2ah'\\v=\sqrt{u^2+2ah'}=\sqrt{(15)^2+2(-9.8)(5.74)}=10.6 m/s

And therefore, the momentum of the ball here is

p'=mv'=(0.1)(10.6)=1.06 kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
______________ waves move perpendicular to their energy transport, while ____________ waves move parallel to their energy transp
Mademuasel [1]
<span>Transverse waves waves move perpendicular to their energy transport, while </span><span>Longitudinal waves</span> waves move parallel to their energy transport.


4 0
4 years ago
A truck has a velocity of 25 m/s and a momentum of 25.000 kg*m/s. What is its<br> mass?
Andrew [12]

Answer:

1000kg

Explanation:

We can use the equation "p=mv"

  • p is the momentum in kg m/s
  • m is the mass measured in kg
  • v is the velocity measured in m/s

If we rearrange the equation to find mass (m), then the equation becomes:

m=p/v

We can substitute in the values of p and v as they are already given in the question.

  • p=25,000 kg m/s
  • v= 25 m/s

So, now we just substitute in the values to get our answer.

m=p/v

m=25,000/25

m=1000kg

3 0
3 years ago
~choices below~
mart [117]
A is the correct answer
5 0
4 years ago
Read 2 more answers
A steel column is 3 m long and 0.4 m diameter. It carries a load of 50 MN so that 5.967 mm is elongates more. Find the modulus o
Alex787 [66]

Answer:

E=2.0*10^{11}N/m^{2}

Explanation:

<u>Relation between stress and Force:</u>

\sigma=\frac{F}{A}=\frac{F}{\pi*d^{2}/4}

<u>Relation between stress and strain:</u>

Young's modulus is defined by the ratio of longitudinal stress σ , to the longitudinal strain ε:

E=\frac{\sigma}{\epsilon}

\epsilon=\frac{\Delta l}{l}

So:

E=\frac{F*l}{\pi*d^{2}/4*\Delta l}=\frac{50*10^{6}*3}{\pi*(0.4^{2}/4)*5.967*10^{-3}}=2*10^{11}N/m^2

8 0
3 years ago
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