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avanturin [10]
3 years ago
9

Two blocks are connected by a rope, as shown below. The masses of the blocks are 10kg for the lower block and 5kg for the upper

block . An upward applied force of magnitude F acts on the upper block. If F = 450N which of the following predictions about the acceleration of the two block system is correct?
1) The system accelerates downward with a magnitude 2g
2) The system accelerates downward with a magnitude 3g
3) The system accelerates upward with a magnitude 2g
4) The system accelerates upward with a magnitude 3g

Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:hjks

Explanation:

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nadezda [96]
The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,
                                     d = ((Vf)² - (Vi)²) / 2g
Substituting the known values,
                                     d = ((96 ft/s)² - 0))/ (2x32.2)
The value of d is 143.10 ft. 
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3 years ago
You throw a 50.0g blob of clay directly at the wall with an initial velocity of -5.00 m/s i. The clay sticks to the wall, and th
Whitepunk [10]

Answer:0.25 kg-m/s

Explanation:

Given

mass of blob m=50 gm

initial velocity u=-5 m/s\ \hat{i}

time of collision t=20 ms

we know Impulse is equal to change in momentum

initial momentum P_i=mu

P_i=50\times 10^{-3}\times (-5)=-0.25 kg-m/s

Final momentum P_f=50\times 10^{-3}v

P_f=0 as final velocity is zero

Impulse J=P_f-P_i

J=0-(-0.25)

J=0.25 kg-m/s

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3 years ago
How does the media restrict what is discussed in the pubic sphere
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Public sphere is a concept created in the 18th century and further developed by Jürgen Habermas, who stated that the public sphere was characterized by it's critical nature in contraposition to the representative nature of the feudal system
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3 years ago
True or False
Ann [662]
The is true because I said so
7 0
2 years ago
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It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass
vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

v^{2}=u^{2}+2\cdot a \cdot s

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/Sec^{2}

s= Distance traveled before stop m

Case 1

u=  13 m/sec, v=0, s= 57.46 m, a=?

0^{2} = 13^{2}  + 2 \cdot a \cdot57.46

a = -1.47 m/Sec^{2} (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/Sec^{2} (since same friction force is applied)

v^{2} = 29^{2}  - 2 \cdot 1.47 \cdot S

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

4 0
3 years ago
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