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slava [35]
3 years ago
15

Using a screwdriver to pry off the lid to a paint can is an example of a second class lever.

Physics
2 answers:
Serggg [28]3 years ago
8 0
Is this a question? Please provide more information.
erastovalidia [21]3 years ago
8 0
I believe the answer is false.
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2. A brick is sitting on a building 22 m high. It has a mass of 7.9 kg. What amount of potential
Citrus2011 [14]

Answer:

1703.24J

Explanation:

Given parameters:

Mass of brick  = 7.9kg

Height of building  = 22m

Unknown:

Potential energy of the brick  = ?

Solution:

The potential energy of a body is the energy at rest of the body. Mathematically;

 

         P.E = mgh

m is the mass of the brick

g is the acceleration due to gravity

h is the height of the building

  Insert the given parameters and solve;

        P.E  = 7.9 x 9.8 x 22  = 1703.24J

6 0
3 years ago
What dose nuclear reactions produce?
aleksandrvk [35]

Answer:

a new chromebook for you and you will get to know the other one that

7 0
2 years ago
Anyone willing to help?
grigory [225]

Answer:

I think it is "A" because the wind systems are created by uneven heating of Earth's surface.It also may help form large global wind patterns.

Explanation:

5 0
2 years ago
Read 2 more answers
If you can run at a speed of 8 miles per hour and you want to run to the store 16 miles away, how
MArishka [77]

Answer:

16÷8=2

Explanation:

if you run 8 mi an hour than in 16 mi you would have run 2 hours

3 0
2 years ago
What quantity of heat is needed to convert 1 kg of ice at -13 degrees C to steam at 100 degrees C?
Effectus [21]

Answer:

Heat energy needed = 3036.17 kJ

Explanation:

We have

     heat of fusion of water = 334 J/g

     heat of vaporization of water = 2257 J/g

     specific heat of ice = 2.09 J/g·°C

     specific heat of water = 4.18 J/g·°C

     specific heat of steam = 2.09 J/g·°C

Here wee need to convert 1 kg ice from -13°C to vapor at 100°C

First the ice changes to -13°C from 0°C , then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

Mass of water = 1000 g

Heat energy required to change ice temperature from -13°C to 0°C

          H₁ = mcΔT = 1000 x 2.09 x 13 = 27.17 kJ

Heat energy required to change ice from 0°C to water at 0°C

          H₂ = mL = 1000 x 334 = 334 kJ

Heat energy required to change water temperature from 0°C to 100°C  

          H₃ = mcΔT = 1000 x 4.18 x 100 = 418 kJ    

Heat energy required to change water from 100°C to steam at 100°C  

          H₄ = mL = 1000 x 2257 = 2257 kJ    

Total heat energy required

          H = H₁ +  H₂ + H₃ + H₄ = 27.17 + 334 + 418 +2257 = 3036.17 kJ

Heat energy needed = 3036.17 kJ

5 0
3 years ago
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