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Semenov [28]
4 years ago
9

What material has the highest strength to weight ratio?

Engineering
2 answers:
Novay_Z [31]4 years ago
7 0
B I think, does it ask you why as well?
Lana71 [14]4 years ago
7 0

Answer: I know it's not up there but this is what I got

Explanation: MIT's graphene material has the world's best strength to weight ratio: a team of researchers at MIT has designed one of the strongest and lightweight materials in the world, by compressing and fusing flakes of graphene.

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Which step in reverse engineering can take place once the general information about the purpose and
Liono4ka [1.6K]

Answer:

Visual analysis

Explanation:

Reverse engineering is the reproduction of another manufacture's product after proper examining the way it was constructed or designed and its composition.

The stages of reverse engineering are;

  • Implementation recovery that involves quick learning about application and preparation of an initial model
  • Design recovery where you undo the previous database mechanics structures and change to recovery foreign main references.
  • Analysis recovery that removes design artifacts and eliminate any errors in the model.

The step of visual analysis involves taking something apart and analyzing its working in details. Here the items observed are;

  • Aesthetics that are concerned with the physical appearance of the product
  • Elements which are the individual building blocks of the design.

6 0
3 years ago
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Elan Coil [88]
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4 0
3 years ago
Read 2 more answers
Express the Internal Energy and Entropy as a Function of T and V for a homogeneous fluid. Develop the same relations using the i
DedPeter [7]

Answer:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

Explanation:

The internal energy is equal to:

dU=C_{v} dT+(T(\frac{\delta P}{\delta T} )_{v} -P)dV

The entropy is equal to:

dS=C_{v} \frac{dT}{T} +(\frac{\delta P}{\delta T} )_{v} dV

If we write the pressure derivative in terms of isothermal compresibility and volume expansivity, we have

\frac{\delta P}{\delta T}=\frac{\beta }{\kappa }

Replacing:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

4 0
3 years ago
The symmetrical load below is connected to a three-phase network. A line current of 25A has been measured. The load resistors ha
boyakko [2]

Answer:

The line voltage of the three phase network is 346.41 V

Explanation:

Star Connected Load

Resistance, R₁ = R₂ = R₃ = 18 Ω

For a star connected load, the line current = the phase current, that is we have

I_L = 25 \, A =  I_{Ph}

Whereby the the voltage across each resistance = V_R is given by the relation;

V_R = I_{Ph} × R

Hence;

V_{Ph} = V_R = I_{Ph} × R  = 25 × 8 = 200 V

Therefore we have;

The line voltage, V_{L} = √3 × V_{Ph} = √3 × 200 = 346.41 V.

Hence, the line voltage of the three phase network = 346.41 V.

3 0
4 years ago
The artifacts that expand what humans are able to do are called:.?
omeli [17]
Where you from?England has so many school subjects,but my country hasn’t got it.Do you like it
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3 years ago
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