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3 years ago

11

Can someone please do this for me? I’m so behind on other work for different classes and this one is due today! please I’d appre

ciate it

1 answer:

Soloha48 [4]3 years ago

5 0

Answer:

Look up lock puzzles (if you like those), or cool cars, or something that you really like and put that as your thing.

Explanation:

You might be interested in

Define denial and identify three of your own examples of denial (they can be from your own life or someone else's). In 300 words

Fantom [35]

Answer:

Denial is a defense mechanism which allows an individual not to accept the truth about a painful experience or distress.

Explanation:

Denial is a way of coping with distress. Denial means trying to reject the truth about a situation. It could be denying the truth about your personal situation or about someone else like your friends, parents or siblings.

Denial is a defense mechanism used to protect oneself against accepting a painful experience or situation in life.

Denial could be helpful or harmful.

It can be helpful when one begin to take action about a problem by seeking for help.

It could be harmful if you don't seek for help when in distress.

A person engaged in denial is trying to stay sane and act normal like everything is alright with he/she. The person tries to block negative thought and focus on more positive thoughts.

Example of denial

1) A young lady who just experienced a breakup from her boyfriend who she truly loves but act like the breakup doesn't affect her or that she doesn't love the guy.

2) A 21 year old person who has cancer and has about 10 months to live have plans of celebrating his/her 25th birthday in a big way

3) When someone is harboring the thought that coronavirus is not real or it is not a serious disease.

3 0

4 years ago

Consider two different types of motors. Motor A has a characteristic life of 4100 hours (based on a MTTF of 4650 hours) and a sh

Daniel [21]

Answer:B

Explanation:

Given

For motor A

Characteristic life(r)=4100 hr

MTTF=4650 hrs

shape factor(B )=0.8

For motor B

Characteristic life(r)=336 hr

MTTF=300 hr

Shape Factor (B)=3

Reliability for 100 hours

$R_a=e^{-\left ( \frac{T-r}{n}\right )B}$

$R_a=e^{-\left ( \frac{4650-4100}{100}\right )0.8}$

$R_a=e^{-4.4}=0.01227$

For B

$R_b=e^{-\left ( \frac{300-336}{100}\right )3}$

$R_b=e^{1.08}=2.944$

B is better for 100 hours

(b)For 750 hours

$R_a=e^{-0.5866}=0.55621$

$R_b=e^{0.144}=1.154$

So here B is more Reliable.

3 0

3 years ago

2. Similar to problem 1, assume your computer system has a 32-bit byte-addressable architecture where addresses and data are eac

andreev551 [17]

Question:

The question is not complete. The question to answer was not added. See below the possible question and the answer.

a. How many blocks are in the cache with this new arrangement?

b. Calculate the number of bits in each of the Tag, Index, and Offset fields of the memory address.

C. Using the values calculated in part b, what is the actual total size of the cache including data, tags, and valid bits?

Answer:

(a) Number of blocks = 512 blocks

(b) Tag is 18

(c) Total size of the cache = 8388608 bytes

Explanation:

a .

block size = 32 bytes

cache size = 16384 bytes

No.of blocks = 16384 / 32

No.pf blocks = 512 blocks

b.

Total address size = 32 bits

Address bits = Tag + Line index +block offset

Block Size = 32 bytes.

So block size = 25 bytes.

Hence Offset is 5

No . of Cache blocks = 512 blocks = 29 blocks

Hence line offset is 9

We know that Address bits = Tag + Line index +block offset

So , 32 =tag+9+5

tag = 32-(9+5)

So Tag is 18

c.

Data bits = 32 bits

Tag=18 bits

Valid bit is 1 bit

so Total cache size = 25+218+20

= 223

=8388608 bytes

7 0

4 years ago

A normal shock wave takes place during the flow of air at a Mach number of 1.8. The static pressure and temperature of the air u

Darina [25.2K]

Answer:

The pressure upstream and downstream of a shock wave are related as

$\frac{P_{1}}{P_{o}}=\frac{2\gamma M^{2}-(\gamma -1)}{\gamma +1}$

where,

$\gamma$ = Specific Heat ratio of air

M = Mach number upstream

We know that $\gamma _{air}=1.4$

Applying values we get

$\frac{P_{1}}{100kPa}=\frac{2\times 1.4\times 1.8^{2}-(1.4 -1)}{1.4 +1}\\\\\frac{P_{1}}{100kPa}=3.61\\\\\therefore P_{1}=361.33kPa(Absloute)$

Similarly the temperature downstream is obtained by the relation

$\frac{T_{1}}{T_{o}}=\frac{[2\gamma M^{2}-(\gamma -1)][(\gamma -1)M^{2}+2]}{(\gamma +1)^{2}M^{2}}$

Applying values we get

$\frac{T_{1}}{423}=\frac{[2\times 1.4\times 1.8^{2}-(1.4-1)][(1.4-1)1.8^{2}+2]}{(1.4+1)^{2}\times 1.8^{2}}\\\\\therefore \frac{T_{1}}{423}=1.53\\\\\therefore T_{1}=647.85K=374.85^{o}C$

The Mach number downstream is obtained by the relation

$M_{d}^{2}=\frac{(\gamma -1)M^{2}+2}{2\gamma M^{2}-(\gamma -1)}\\\\\therefore M_{d}^{2}=\frac{(1.40-1)\times 1.8^{2}+2}{2\times1.4\times 1.8^{2}-(1.4-1)}\\\\\therefore M_{d}^{2}=0.38\\\\M_{d}=0.616$

3 0

4 years ago

Which situation might cause potential hazards at a construction site?

nata0808 [166]

Answer:

D. protruding steel rebars .. #answerwithquality #BAL

5 0

3 years ago

Read 2 more answers