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3 years ago

PROBLEM IN PICTURE HELP ME DEAR GODDDDDD UGHHH NONONO I HAVE 2 MINUTES TO FINISH THIS ❕❗️❕❗️❗️❕❕❕❕❗️❕❕❗️❕❗️❗️❗️❕‼️‼️‼️‼️❗️‼️❗️

Engineering

2 answers:

Elan Coil [88]3 years ago

4 0

Thx :) so much :))))))

Julli [10]3 years ago

4 0

Answer:

Hey mate.....

Explanation:

THANK YOU SO MUCH!!!!!!!!!!!!!!

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It has a piece of 1045 steel with the following dimensions, length of 80 cm, width of 30 cm, and a height of 15 cm. In this piec

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Answer:

material remove in 3 min is 16790.4 mm³/s

Explanation:

given data

length L = 80 cm = 800 mm

width W = 30 cm

height H = 15 cm

make grove length = 80 cm

width = 8 cm

depth = 10 cm

mill toll diameter = 4 mm

axial cutting depth = 20 mm

to find out

How much material removed in 3 minutes

solution

first we find time taken for length of advance that is

time = $\frac{length}{advance}$

here advance is given as 0.001166 mts / sec

so time = $\frac{800}}{0.001166*1000}$

time = 686.106 seconds

now we find material remove rate that is

remove rate = mill toll rate × axial cutting depth × advance

remove rate = 4 × 20×0.001166 ×1000

remove rate = 93.28 mm³/s

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3 years ago

A two-dimensional flow field described by

Oduvanchick [21]

Answer:

the answer is

Explanation:

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