Answer:
i think the second option
Step-by-step explanation:
follow me on my insta a.cc.o.u.n.t below
<h2>
<em><u>"</u></em><em><u>A</u></em><em><u>T</u></em><em><u>T</u></em><em><u>I</u></em><em><u>C</u></em><em><u>U</u></em><em><u>S</u></em><em><u>_</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>E</u></em><em><u>T</u></em><em><u>L</u></em><em><u>O</u></em><em><u>V</u></em><em><u>E</u></em><em><u>R</u></em><em><u>"</u></em></h2>
for these you need to rearrange the equations and do substitutions.
#3 = if x+y=5 then you know x = 5-y
now substitute that equation for x in the 2nd one so x + 2y = 8 becomes
5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3
now replace y with 3 in the first equation x = 5-3 so x = 2
so (2,3) is the answer
same type of work for #4
2x-y=6 ,S0 y = 2X+6
so now you have 4x+2(2x+6)=-4
that becomes 4x +4x+12 = -4
8x+8 = 1, x =1
y = 2(1)-6 = -4
so answer is (1,-4)
Answer:7 3/7 < 7 2/5
Step-by-step explanation:
Answer:
Hi! The answer to your question is C. 52
Step-by-step explanation:
☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆
☆Brainliest is greatly appreciated!☆
Hope this helps!
- Brooklynn Deka
Answer:
2x + 5y + 28 = 0
Step-by-step explanation:
since they are perpendicular,
m1 ×m2 = -1
5/2 × m2 = -1
m2 = -2/5
now,
y -y1 = M (x-x1)
y - (-4) = -2/5 ( x - (-4) )
y +4 = -2/5 ( x + 4 )
5 ( y +4 ) = -2 ( x+4)
5y +20 = -2x - 8
2x + 5y +20 + 8 =0
2x + 5y + 28 = 0
