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joja [24]
3 years ago
8

There were two partners Fred and jack Fred can paint 3 paintings per hour, and jack can paint 2 paintings per hour Fred has alre

ady painted 9 paintings and Jack has completed 10 paintings they took a break when they finished the same total number of paintings how many paintings did they each make in total? How long will it take each painter?
Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

bbbdbrhrhfhdbfhfhchchfhffh

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grandymaker [24]

Answer:

x = -1

Step-by-step explanation:

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The dough for the world's largest pizza was baked in 5,234 batches. Suppose it took the chefs 3 hours to bake the first 327 batc
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The dough for the world's largest pizza was baked in 5,234 batches. Suppose it took the chefs 3 hours to bake the first 327 batches, and they bake the rest of the batches at the same rate. How long would it take to bake all the batches? Explain your reasoning.

3 0
3 years ago
The product of 9 and a number is 12 less than three times that number.<br><br> What is the number?
Alenkasestr [34]
So let me give you the answer with procedure so that you can understand it better:
Let x = Number 

<span>Product of 9 and Number:</span>
<span>9x </span>
<span>is 12 less than 3 times that number. So: </span>
<span>3x - 12 </span>
<span>Set them equal and solve for x like this:</span>
<span>9x = 3x - 12 </span>
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<span>x = -2
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5 0
3 years ago
Find the shaded area of the figure. Please help I am giving brainliest
Varvara68 [4.7K]

Answer:

do u mean the degree? if u do then it would be 60

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the following quotient?
mamaluj [8]

Answer:

A.2(3^{\frac{1}{3}})-\sqrt[3]{18}

Step-by-step explanation:

We are given that

\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})

We have to find the quotient.

\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})

\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})

2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})

Using the property

(ab)^n=a^n\cdot b^n

2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})

Using the property

\frac{a^x}{a^y}=a^{x-y}

2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}

2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Hence, the quotient of \frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}}) is given by

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Option A is correct.

4 0
2 years ago
Read 2 more answers
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