The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
- The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave.
- The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.
- Oscillation is defined as the process in which an object moves in the "back and forth motion."
- Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.
- Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.
- Amplitude is the breadth or magnitude of the waves.
Learn more about "Oscillation" here:
brainly.com/question/9820984
I believe the answer is coal
Explanation:
Hydraulic Pressure-Control, On-Off Deluge Valve
FP-400Y-5DC
The BERMAD model 400Y-5DC is an elastomeric, hydraulic line pressure operated deluge valve, designed specifically for advanced fire protection systems and the latest industry standards. The 400Y-5DC is activated by a hydraulically operated relay valve, through which opening and closing of the valve can be controlled either with a remote hydraulic command or with a wet pilot line with closed fusible plugs. An integral pressure reducing pilot valve ensures a precise, stable, pre-set downstream water pressure. The optional valve position indicator can include a limit switch suitable for Fire & Gas monitoring systems. The 400Y-5DC is ideal for systems that combine a remote wet pilot line with a high pressure water supply.
Answer:
violet has the highest frequency
Explanation:
Answer:
(a) The total energy of the object at any point in its motion is 0.0416 J
(b) The amplitude of the motion is 0.0167 m
(c) The maximum speed attained by the object during its motion is 0.577 m/s
Explanation:
Given;
mass of the toy, m = 0.25 kg
force constant of the spring, k = 300 N/m
displacement of the toy, x = 0.012 m
speed of the toy, v = 0.4 m/s
(a) The total energy of the object at any point in its motion
E = ¹/₂mv² + ¹/₂kx²
E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²
E = 0.0416 J
(b) the amplitude of the motion
E = ¹/₂KA²
(c) the maximum speed attained by the object during its motion
