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vredina [299]
3 years ago
9

What is the beat frequency of two keys on a phone, one with a frequency of 210 Hz and the other one with a frequency of 280 Hz?

Physics
1 answer:
vodka [1.7K]3 years ago
6 0
The best frequency should be 70 Hz you simply find the difference between 280 Hz and 210 Hz
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According to Newton’s Third Law of Motion, how are action and reaction forces related. Provide a full explanation with an exampl
hammer [34]
For every action, there is an equal and opposite reaction. For example, take a cup on a table. The weight of the cup is the action, and the reason the cup does not sink through the table is because the table exerts an equal reaction force which is opposite to the action of the cup.

Hope this helps!
5 0
3 years ago
A car leaves a garage at 10 mph. it speeds up to 20 miles per hour in the city and eventually increases to 50 miles per hour in
LekaFEV [45]

Average speed = (total distance covered) / (time to cover the distance)

= (50 miles) / (1.5 hours)

= (50/1.5) miles/hours

= (33 and 1/3) mph .

We don't care about all that other "data" given earlier in the question.
We only need to know the total distance covered and the time it took
to cover the distance.
4 0
3 years ago
The Petronas twin towers in Malaysia and the Chicago Sears tower have heights of about 452 m and 443 m respectively. If objects
fredd [130]

Answer:

0.09 s

Explanation:

From the second equation of motion,

S=ut+\frac{1}{2}at^{2}

Here, u is the initial velocity, a is the acceleration due to gravity, t is time taken, and S is the total displacement or distance.

From the given problem,

initial velocity is zero for both the case.

And the distance of twin  tower of malaysia is, S_{1}=452m

And the distance of Sears tower of Chicago is, S_{1}=443m

Now,rearrange the distance equation for t.

t=\sqrt{\frac{2S}{a} }

So time difference.

\Delta t=\sqrt{\frac{2(452)}{9.8} }-\sqrt{\frac{2(443)}{9.8} }\\\Delta t=\sqrt{92.244898}-\sqrt{90.4081633}  \\\Delta t=9.60 s-9.51s\\\Delta t=0.09 s

Therefore, the difference in time, object will reach the ground is 0.09 s

8 0
3 years ago
Hi people; there's a question that has been so confusing for me and a friend of mine.
Alborosie

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32

In our case x = 0, then y will be:

(0^{\circ}C * \frac{9}{5})+32=32

y=32^{\circ}F

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

0^{\circ}C+0^{\circ}C=32^{\circ}F

I hope it helps you!              

7 0
3 years ago
A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an a
goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is  -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

Learn more about forces here: brainly.com/question/12970081

#SPJ1

7 0
2 years ago
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