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3 years ago

What is the beat frequency of two keys on a phone, one with a frequency of 210 Hz and the other one with a frequency of 280 Hz?

Physics

1 answer:

vodka [1.7K]3 years ago

6 0

The best frequency should be 70 Hz you simply find the difference between 280 Hz and 210 Hz

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What is the rarefaction of a longitudinal

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The answer Is B! Good luck

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2 years ago

A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west. what impulse is required to decrease the speed of t

zzz [600]

The impulse required to decrease the speed of the boat is equal to the variation of momentum of the boat:
$J=\Delta p=m \Delta v$
where
m=225 kg is the mass of the boat
$\Delta v=v_f-v_i=15 m/s-21 m/s=-6 m/s$ is the variation of velocity of the boat
By substituting the numbers into the first equation, we find the impulse:
$J=m\Delta v=(225 kg)(-6 m/s)=-1350 N s$
and the negative sign means the direction of the impulse is against the direction of motion of the boat.

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3 years ago

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Mo is on a baseball team and hears that a ball thrown at a 45 degree angle from the ground will travel the furthest distance. Ho

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Answer:

Explanation:

Usually the angle between the y axis and x axis is 90° and we know that for furthest travel the degree angle must be 45° with the horizontal, Mo must release the ball about halfway between straight ahead and straight up

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3 years ago

The ray diagram shows a vase that is placed beyond the center of curvature of a concave mirror.

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The image will form in the vicinity of F. Its nature will be small and inverted

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3 years ago

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Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10

11111nata11111 [884]

Answer:

$1.62\times 10^{-8}\ \text{s}$

Explanation:

$\epsilon_0$ = Vacuum permittivity = $8.854\times 10^{-12}\ \text{F/m}$

$A$ = Area = $10\times 2\times 10^{-4}\ \text{m}^2$

$d$ = Distance between plates = 1 mm

$V_c$ = Changed voltage = 60 V

$V$ = Initial voltage = 100 V

$R$ = Resistance = $1000\ \Omega$

Capacitance is given by

$C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.854\times 10^{-12}\times 10\times 2\times 10^{-4}}{1\times 10^{-3}}\\\Rightarrow C=1.7708\times 10^{-11}\ \text{F}$

We have the relation

$V_c=V(1-e^{-\dfrac{t}{CR}})\\\Rightarrow e^{-\dfrac{t}{CR}}=1-\dfrac{V_c}{V}\\\Rightarrow -\dfrac{t}{CR}=\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-CR\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-1.7708\times 10^{-11}\times 1000\ln(1-\dfrac{60}{100})\\\Rightarrow t=1.62\times 10^{-8}\ \text{s}$

The time taken for the potential difference to reach the required level is $1.62\times 10^{-8}\ \text{s}$ .

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2 years ago