A student is flying west on a school trip from Winnipeg to Calgary in a jet that has an air velocity of 792 km/h.The direction t
1 answer:
Answer:
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] is 4.5° S of W
Explanation:
The given parameters are;
Velocity of Jet = 792 km/h
Direction of jet velocity = West
Velocity of wind = 62.0 km/h
Direction of wind velocity = North
Therefore, the jet has to have a component of 62.0 km/h South of West to compensate for the wind velocity
The direction of the plane, θ° South of West (S of W) to compensate for the wind is given as follows;
Therefore;
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] = 4.5° S of W.
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The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by
where,
Since, T=37+273 K = 310 K
v = 331 m/s
Using this, we get:
Hence, the fundamental frequency is 367.42 Hz.
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Answer:
The work is done by the truck pulling the car 1 km is 1,212,436 J
Explanation:
Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.
So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.
In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.
The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:
Work= Force*Distante* cos (θ)
In this case:
- Force= 1,400 N= 1,400
- Distance= 1 km= 1,000 m
- θ= Angle that exists between the direction of the force and the direction= 30°
Replacing:
Work= 1,400 N* 1,000 m* cos (30°)
Work= 1,212,435. 565 Joule≅ 1,212,436 J
<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>
Answer: 247.67 V
Explanation:
Given
Potential At A
Potential at
when particle starts from A it reaches with velocity at Point while when it starts from C it reaches at point B with velocity
Suppose m is the mass of Particle
Change in Kinetic Energy of particle moving under the Potential From A to B
Change in Kinetic Energy of particle moving under the Potential From C to B
Divide 1 and 2 we get
on solving we get