(1 point) find the point pp where the line x=1+t,y=2t,z=−3tx=1+t,y=2t,z=−3t intersects the plane x+y−z=1.
1 answer:
Sub in values for x,y,z into plane equation.
(1+t) + 2t - (-3t) = 1
Solve for 't'
6t + 1 = 1
t = 0
Sub back in t=0 into line to find point.
x = 1+0 = 1
y = 2(0) = 0
z = -3(0) = 0
Answer : The point is (1,0,0)
You might be interested in
Answer:
$10800
Step-by-step explanation:
Answer:
x = 6.9
Step-by-step explanation:
solve for x
Answer:
6. xint=-7
yint=-3
7. xint=-7
yint=-5
Step-by-step explanation:
Answer:
the answer is c go ahead and click it
Step-by-step explanation:
Answer:
x² - 4x = 21
x² - 4x - 21 = 0
x² - 7x + 3x - 21 = 0
x( x - 7 ) + 3 ( x - 7 ) = 0
( x + 3 ) ( x - 7 ) = 0
x + 3 = 0 and x - 7 = 0
x = -3 and x = 7