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Dmitrij [34]
2 years ago
9

500 kg car takes a car of radius 50m with a velocity of 36km/hr.the centripetal force is​

Physics
1 answer:
mylen [45]2 years ago
3 0

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>car </u><u>weighing </u><u>5</u><u>0</u><u>0</u><u> </u><u>kg </u><u>takes </u><u>a </u><u>turn </u><u>of </u><u>radius </u><u>5</u><u>0</u><u>m</u><u> </u><u>with </u><u>a </u><u>velocity</u><u> </u><u>of </u><u>3</u><u>6</u><u> </u><u>km/</u><u>hr</u>

  • To calculate - <u>the </u><u>centripetal </u><u>force</u>

  • Formula used -

\bold{F =  \frac{mv {}^{2} }{r}}  \\

where ,

<u>r </u><u>=</u><u> </u><u>radius</u>

<u>m </u><u>=</u><u> </u><u>mass </u><u>of </u><u>the </u><u>object</u>

<u>v </u><u>=</u><u> </u><u>velocity</u><u> </u><u>with </u><u>which </u><u>the </u><u>object </u><u>moves</u>

According to Question ,

<u>Mass </u><u>of </u><u>car </u><u>=</u><u> </u><u>5</u><u>0</u><u>0</u><u> </u><u>kg</u>

<u>Radius </u><u>of </u><u>the </u><u>round </u><u>=</u><u> </u><u>5</u><u>0</u><u> </u><u>m </u>

<u>velocity </u><u>of </u><u>car </u><u>=</u><u> </u><u>3</u><u>6</u><u> </u><u>km/</u><u>hr</u>

velocity = \cancel{36 }\times  \frac{5}{\cancel{18}}  \\  \\ \implies \: velocity = 10 \: ms {}^{ - 1}

<u>Substituting</u><u> </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

F =  \frac{\cancel{500} \times 10 {}^{2} }{\cancel{50}}  \\  \\ \dashrightarrow \: F = 10 \times 10 {}^{2}  \\  \\ \dashrightarrow \: F = 1000 \: N

hope helpful ~

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Answer:

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Explanation:

The computation is shown below:

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A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos
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His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

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Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

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