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tester [92]
2 years ago
14

Astronaut John's mass is 75 kg. He is floating at rest in the space station holding a 5.0 kg pillow. When his friend Bill enters

the room, John throws the pillow at Bill with a velocity of 25 m/s. Immediately after letting go of the pillow, what is John's velocity?
A.
1.7 m/s towards Bill
B.
1.7 m/s away from Bill
C.
15 m/s towards Bill
D.
15 m/s away from Bill
Physics
1 answer:
Murljashka [212]2 years ago
4 0

Answer:

my name is Deepika Pandey anion I am 9 years old my father name is Dinesh Pandey my name is and my sister name is sister name is a

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I need help on this question!! Please answer asap!
valentina_108 [34]

Answer:

hub    moon     merc   saturn   sun    galaxy    deep field

Explanation:

5 0
2 years ago
If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules,
Kitty [74]

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

7 0
2 years ago
Calculate the impulse imparted when a 3,000-kg car hits a wall at 60 . m/s and comes to a stop.
Pani-rosa [81]

Impulse = change in momentum


The answer is 0.

7 0
2 years ago
Easy chemical formula question (9th grade)
kogti [31]

Silver and Silver (II) are different because silver (II) has more than 1 electric charge. It has 2! lol

4 0
3 years ago
Calculate the kinetic energy of a 64.g bullet moving at a speed of 411.ms . Round your answer to 2 significant digits.
Mandarinka [93]

Answer:

The kinetic energy of the bullet is 5.4 × 10³ J

Explanation:

Hi there!

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass of the bullet.

v = speed of the bullet.

Let´s convert the mass unit to kg so that our result is in Joules:

64 g · ( 1 kg / 1000 g) = 0.064 kg

Then, the kinetic energy will be the following:

KE = 1/2 · 0.064 kg · (411 m/s)²

KE = 5.4 × 10³ J

8 0
2 years ago
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