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3 years ago

Why do atoms do group 1 element lose electrons to form cations

Physics

1 answer:

Mrac [35]3 years ago

8 0

Answer:

when a element of 1 group take part in reaction, its atom looses outer electron and form positively charged ions called Cation.

Explanation:

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What is the frequency heard by a person driving at 15 m/s toward a factory whistle emitting a

zmey [24]

Answer:

835.29 Hz

Explanation:

When moving towards the source of sound, frequency will be given by

f*=f(vd+v)/v

Where f is the freqiency of the source, vd is the driving speed, v is the speed of sound in air, f* is the inkown frequency when moving forward.

Substituting 800 Hz for f, 340 m/s for v and 15 m/s for vd then

f*=800(15+340)/340=835.29411764704 Hz

Rounded off, the frequency is approximately 835.29 Hz

4 0

3 years ago

find the velocity of the object for all relevent times find the position of the object for all relevent times a softball is popp

KATRIN_1 [288]

Answer:

whats the formula

Explanation:

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2 years ago

The decomposition of ammonia to the elements is a first-order reaction with a half-life of 200 s at a certain temperature. How l

Feliz [49]

Based on the half-life of the reaction, time taken for the partial pressure of ammonia to decrease from 0.100 atm to 0.00625 atm is 800 seconds.

<h3>What is the half-life of a substance?</h3>

The half-life of a substance is the time taken for half the amount of atoms present in that substance to decay.

The half-life of the reaction is 200 seconds.

After, one half-life, pressure reduces to 0.0500 atm

After, two half-lives, pressure reduces to 0.0250 atm

After, three half-lives, pressure reduces to 0.01250 atm

After, four half-lives, pressure reduces to 0.00625 atm

Time taken = 4 * 200 = 800 seconds

Therefore, time taken for the partial pressure of ammonia to decrease from 0.100 atm to 0.00625 atm is 800 seconds.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

7 0

1 year ago

Radon is the heaviest naturally radioactive ________________ gas. A) noble B) halogen C) group 1 D) diatomic

Sever21 [200]

(A) noble gases / group 18

6 0

3 years ago

Read 2 more answers

Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by

bixtya [17]

Answer:

v = 0.99 c = 2.99 x 10⁸ m/s

Explanation:

From the special theory of relativity:

$t = \frac{t_o}{\sqrt{1-\frac{v^2}{c^2} } }\\$

where,

v = speed of travel = ?

c = speed of light = 3 x 10⁸ m/s

t = time measured on earth = 90 years

t₀ = time measured in moving frame = 6 months = 0.5 year

Therefore,

$90\ yr = \frac{0.5\ yr}{\sqrt{1-\frac{v^2}{c^2} } } \\\\\\\sqrt{1-\frac{v^2}{c^2}} = \frac{0.5\ yr}{90\ yr}\\ 1-\frac{v^2}{c^2} = 0.00003086\\\frac{v^2}{c^2} = 1-0.00003086\\$

8 0

3 years ago