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3 years ago

I NEED HELP!! PLEASE HELP ME

Physics

1 answer:

vesna_86 [32]3 years ago

8 0

Answer:

but I can tomorrow if you have time can you come to the meeting tonight but yyyy the person who is this and what

Explanation:

gyyyyyyyyyyyyyyyyy the number of the person who is this and what is the

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While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p

algol13

Answer:

True

Explanation:

In Massachusetts it's illegal to drive while texting or on your phone.

3 0

3 years ago

A particular planet has a moment of inertia of 8.26 × 1036 kg⋅m2 and a mass of 6.54 × 1022 kg. Based on these values, what is th

SVEN [57.7K]

Answer: Correct answer is B = 1.776933× $10^{7}$

Explanation:

Given :

Moment of inertia I = 8.26× $10^{36}$ kg $m^{2}$

Mass of planet m = 6.54× $10^{22}$ kg

Also, Planet is solid sphere so that, Moment of inertia is I = $\frac{2}{5}$ m $R^{2}$ =0.4m $R^{2}$

Where R is radius of planet

Putting into calculation

We get,

I = $\frac{2}{5}$ m $R^{2}$

8.26× $10^{36}$ = 0.4×6.54× $10^{22}$ × $R^{2}$

8.26× $10^{14}$ = 2.616 $R^{2}$

3.15749235× $10^{14}$ = $R^{2}$

R = 1.776933× $10^{7}$

Thus, Correct answer is B = 1.776933× $10^{7}$

3 0

3 years ago

A car accelerates from rest to 37.3 m/s<br> in 7 sec. What is the acceleration?

Sergio039 [100]

Answer:

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Explanation:

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3 years ago

Scientist often use ______________ which are programs that combine what is known about atmospheric circulation

Serggg [28]

Answer:

General circulation model.

Explanation:

A general circulation model (GCM) is a type of climate model that employs a mathematical model of the general circulation of a planetary atmosphere or ocean. GCM uses the Navier–Stokes equations on a rotating sphere with thermodynamic terms for various energy sources (radiation, latent heat). These equations are the basic equations for computer programs used to simulate the Earth's atmosphere or oceans.

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3 years ago

Read 2 more answers

A billiard ball moving at 5 m/s strikes another ball which is initially at rest. After the collision, the first ball moves at a

ziro4ka [17]

Answer:

The velocity of the second ball is approximately 2.588 m/s

The angle direction of the second ball is 75° counterclockwise from the horizontal

Explanation:

The initial velocity of the first billiard ball = 5 m/s

The initial velocity of the billiard ball the first billiard ball strikes = 0 m/s

The final velocity of the first billiard ball = 4.35 m/s

The final direction of motion of the first billiard ball = 30° below its original motion

For perfectly elastic collision, whereby the target is at rest initially, by conservation of momentum, we have;

m₁ × $\underset{v_1}{\rightarrow}$ = m₁· $\underset{v'_1}{\rightarrow}$ + m₂· $\underset{v'_2}{\rightarrow}$

Which gives;

m₁ × 5·i = m₁·((√3)/2×5·i - 2.5·j) + m₂· $\underset{v'_2}{\rightarrow}$

∴ m₂· $\underset{v'_2}{\rightarrow}$ = m₁ × 5·i - m₁·((√3)/2×5·i - 2.5·j)

m₂· $\underset{v'_2}{\rightarrow}$ = m₁ × 5·(1 - √3/2)·i + m₁·2.5·j = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

Therefore, given that the mass of both billiard balls are equal, we have, m₁ = m₂, which gives;

m₂· $\underset{v'_2}{\rightarrow}$ = m₁· $\underset{v'_2}{\rightarrow}$ = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

∴ $\underset{v'_2}{\rightarrow}$ = 2.5·(2 - √3)·i + 2.5·j

The magnitude of the velocity of the second ball is $\underset{v'_2}{\rightarrow}$ = √((2.5·(2 - √3))² + 2.5²) ≈ 2.588 m/s

The direction of the second ball, θ = arctan(2.5/((2.5·(2 - √3))) = 75° counterclockwise from the horizontal.

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3 years ago