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Answer:
(a) 5.056 x 10^-14 N
(b) 5.056 x 10^-14 N
Explanation:
X component of velocity of electron is 1.6 × 10^6 m/s
Y component of velocity of electron is 2.4 × 10^6 m/s
X component of magnetic field is 0.025 T
Y component of magnetic field is -0.16 T
charge on electron, q = - 1.6 x 10^-19 C
Write the velocity and magnetic field in the vector forms.


The force on the charge particle when it is moving in the magnetic field is given by

(a) Force on electron is given by


Magnitude of force is 5.056 x 10^-14 N.
(b) Force on a proton is given by


Magnitude of force is 5.056 x 10^-14 N.
Thus, the magnitude of force remains same but the direction of force is opposite to each other.
Explanation:
Answer:
B. w=12.68rad/s
C. α=3.52rad/s^2
Explanation:
B)
We can solve this problem by taking into account that (as in the uniformly accelerated motion)
( 1 )
where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.
In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have


to calculate the angular speed w we can use
Thus, wf=12.68rad/s
C) We can use our result in B)

I hope this is useful for you
regards
Mechanical Wave cannot travel in space vaccumes, which would be considered "Empty Space" in your situation.