A gas stove uses chemical energy.
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Answer:
d- Earth revolves around the sun.
Explanation:
Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.
This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun.
On the other hand, earth revolution can be defined as a complete trip along a path around the sun. This path is known as an orbit and it typically takes the Earth 365¼ days to complete it's journey around the Sun.
When a constellation (stars) changes its position in the sky, at the same time of the evening and over a period of several weeks; it ultimately implies or is an evidence that Earth revolves around the sun.
Answer:
2 is the numerical answer.
Explanation:
Hello there!
In this case, according to the given information and formula, it is possible for us to remember that equation for the calculation of the average kinetic energy of a gas is:
![KE=\frac{3}{2} \frac{R}{N_A} T](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B3%7D%7B2%7D%20%5Cfrac%7BR%7D%7BN_A%7D%20T)
Whereas R is the universal gas constant, NA the Avogadro's number and T the temperature.
Which means that for the given ratio, we can obtain the value as follows:
![=\frac{\frac{3}{2} \frac{R}{N_A} T_1}{\frac{3}{2} \frac{R}{N_A} T_2} \\\\=\frac{T_1}{T_2} \\\\=\frac{500K}{250K} \\\\=2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Cfrac%7B3%7D%7B2%7D%20%5Cfrac%7BR%7D%7BN_A%7D%20T_1%7D%7B%5Cfrac%7B3%7D%7B2%7D%20%5Cfrac%7BR%7D%7BN_A%7D%20T_2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7BT_1%7D%7BT_2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B500K%7D%7B250K%7D%20%5C%5C%5C%5C%3D2)
Regards!
To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by
![V = \sqrt{\frac{T}{\rho}}](https://tex.z-dn.net/?f=V%20%3D%20%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Crho%7D%7D)
Where,
T = Tension
Linear density
Our data are given by
Tension , T = 70 N
Linear density , ![\rho = 0.7 kg/m](https://tex.z-dn.net/?f=%5Crho%20%3D%200.7%20kg%2Fm)
Amplitude , A = 7 cm = 0.07 m
Period , t = 0.35 s
Replacing our values,
![V = \sqrt{\frac{T}{\rho}}](https://tex.z-dn.net/?f=V%20%3D%20%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Crho%7D%7D)
![V = \sqrt{\frac{70}{0.7}](https://tex.z-dn.net/?f=V%20%3D%20%5Csqrt%7B%5Cfrac%7B70%7D%7B0.7%7D)
![V = 10m/s](https://tex.z-dn.net/?f=V%20%3D%2010m%2Fs)
Speed can also be expressed as
![V = \lambda f](https://tex.z-dn.net/?f=V%20%3D%20%5Clambda%20f)
Re-arrange to find \lambda
![\lambda = \frac{V}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7BV%7D%7Bf%7D)
Where,
f = Frequency,
Which is also described in function of the Period as,
![f = \frac{1}{T}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7BT%7D)
![f = \frac{1}{0.35}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B0.35%7D)
![f = 2.86 Hz](https://tex.z-dn.net/?f=f%20%3D%202.86%20Hz)
Therefore replacing to find ![\lambda](https://tex.z-dn.net/?f=%5Clambda)
![\lambda = \frac{10}{2.86}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B10%7D%7B2.86%7D)
![\lambda = 3.49m](https://tex.z-dn.net/?f=%5Clambda%20%3D%203.49m)
Therefore the wavelength of the waves created in the string is 3.49m