A bird flies 2km to the south, then 0.2km to the north.What is the displacement of the bird ?
2 answers:
Explanation:
It is given that,
A bird flies 2 km to the south, then 0.2 km to the north. The displacement of the bird is equal to the shortest path covered by it.
Initially, the bird is moving in south direction and then it move to north. Displacement can be calculated using difference between initial position and final position.
d = 2.2 km - 0.2 km = 1.8 km
Hence, the displacement of the bird is 1.8 km
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Answer:
8977.7 kg/m^3
Explanation:
Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3
Reading of balance when block is immersed in water = 4.3 N
According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.
Buoyant force = weight of the water displaced by the block
Buoyant force = Volume of water displaced x density of water x g
= 55 x 10^-6 x 1000 x .8 = 0.539 N
True weight of the body = Weight of body in water + buoyant force
m g = 4.3 + 0.539 = 4.839
m = 0.4937 kg
Density of block = mass of block / volume of block
=
Density of block = 8977.7 kg/m^3