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Daniel [21]
3 years ago
14

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

Mathematics
2 answers:
liraira [26]3 years ago
5 0

Answer:12

Step-by-step explanation:

Oduvanchick [21]3 years ago
4 0

Answer:

The value is 12

Step-by-step explanation:

we have

y=-2x+4

Convert to standard form

2x+y=4 ----> equation A

Let

a ----> the missing value

6x+3y=a ----> equation B

we know that

If the system of equations A and B has infinitely solutions, then equation A and equation B are identical

Multiply equation A by 3 both sides

3(2x+y)=3(4)

6x+3y=12 ----> new equation A

Equate new equation A and equation B

a=12

therefore

The value is 12

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Use the half-life equation:

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A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
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In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

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y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

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Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

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Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
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V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
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