Question

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

Answer 1

Answer:12

Step-by-step explanation:

Answer 2

Answer:

The value is 12

Step-by-step explanation:

we have

$y=-2x+4$

Convert to standard form

$2x+y=4$ ----> equation A

Let

a ----> the missing value

$6x+3y=a$ ----> equation B

we know that

If the system of equations A and B has infinitely solutions, then equation A and equation B are identical

Multiply equation A by 3 both sides

$3(2x+y)=3(4)$

$6x+3y=12$ ----> new equation A

Equate new equation A and equation B

$a=12$

therefore

The value is 12