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3 years ago

Solve the system by elimination (show all work)

Mathematics

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

$[1, 1, 0]$

Step-by-step explanation:

{−2x + 2y + 3z = 0

{−2x - y + z = −3 ←

{2x + 3y + 3z = 5 ←

2y + 4z = 2 ↷

{−2x + 2y + 3z = 0 ←

{−2x - y + z = −3

{2x + 3y + 3z = 5 ←

5y + 6z = 5 ↷

{5y + 6z = 5

{2y + 4z = 2

−⅖[5y + 6z = 5]

{−2y - 2⅖z = −2 >> New Temporary Equation

{2y + 4z = 2

____________

1⅗z = 0

___ _

1⅗ 1⅗

$z = 0$ [Plug this back into both equations above to get the y-term of 1, then plugging both z-term and y-term into all three equations at the very top, will give you the x-term of 1]; $1 = y$ ; $1 = x$

I am joyous to assist you anytime.

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