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Luda [366]
3 years ago
14

Solve the system by elimination (show all work)

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

[1, 1, 0]

Step-by-step explanation:

{−2x + 2y + 3z = 0

{−2x - y + z = −3 ←

{2x + 3y + 3z = 5 ←

2y + 4z = 2 ↷

{−2x + 2y + 3z = 0 ←

{−2x - y + z = −3

{2x + 3y + 3z = 5 ←

5y + 6z = 5 ↷

{5y + 6z = 5

{2y + 4z = 2

−⅖[5y + 6z = 5]

{−2y - 2⅖z = −2 >> New Temporary Equation

{2y + 4z = 2

____________

1⅗z = 0

___ _

1⅗ 1⅗

z = 0 [Plug this back into both equations above to get the y-term of 1, then plugging both z-term and y-term into all three equations at the very top, will give you the x-term of 1]; 1 = y; 1 = x

I am joyous to assist you anytime.

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