Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Based on the difference in scores for the basketball team over the six games, the mean difference in scores was 3
<h3>How to find the mean difference in scores?</h3>
The basketball team had 6 games and in these games, their scores were listed as differences in game scores.
The mean of these differences in scores can be found by adding the differences where they won and subtracting the differences where they lost and then dividing by the number of games:
The mean difference in game scores is:
= (7 - 7 + 8 + 9 - 4 + 5) / 6
= 18 / 6
= 3
Find out more on the mean differences at brainly.com/question/11323789
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Answer:
Step-by-step explanation:
Use the Pythagorean theorem. 
a and b are the two side lengths
c is the hypotenuse (value across from the right angle)
Plug in the values that you are given.
Solve for x
x=
115 degrees because there are 180 degrees in a triangle so let the missing angle in the trinagle be x. Then we have x+75+40=180. Solving for x and subtracting that from 180 (supplementary angles) we get 115 degrees.
