The speed (rate) of the plane in still air is <u>1100 kilometers per hour</u> and the speed (rate) of the wind is <u>210 kilometers per hour</u>.
We assume the speed (rate) of the plane in still air to be x kilometers per hour, and the speed (rate) of the wind to be y kilometers per hour.
Thus, flying against the wind, the acting speed (rate) for the plane will be x - y kilometers per hour.
Flying with the wind, the acting speed (rate) for the plane will be x + y kilometers per hour.
We are given that flying against the wind, the airplane travels 6230 kilometers in 7 hours.
Thus, speed (rate) = 6230/7 kilometers per hour = 890 kilometers per hour.
Equating this to the derived speed of the airplane flying against the wind, we get x - y = 890 ... (i).
We are given that flying with the wind, the airplane travels 10480 kilometers in 8 hours.
Thus, speed (rate) = 10480/8 kilometers per hour = 1310 kilometers per hour.
Equating this to the derived speed of the airplane flying with the wind, we get x + y = 1310 ... (i).
Now, on adding equations (i) and (ii), we get:
2x = 2200,
or, x = 1100.
Substituting x = 1100 in (ii), we get:
x + y = 1310,
or, 1100 + y = 1310,
or, y = 1310 - 1100 = 210.
Thus, the speed (rate) of the plane in still air is <u>1100 kilometers per hour</u> and the speed (rate) of the wind is <u>210 kilometers per hour</u>.
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