Two objects are thrown vertically upward, first one, and then, a bit later, the other. Is it (a) possible or (b) impossible that
1 answer:
Answer:
No, it is impossible
Explanation:
Kinematics equation:
if height is maximum:
y=H and Vf=0
so:
<h3>Analysis: From the last equation we see that the maximum height depends ONLY on the initial speed. This means that if both objects reach the same maximum height, then they necessarily need to have the SAME initial velocity. If they have the same initial velocity and in order to reach the maximum height at the SAME time the only way is that they are released at the SAME TIME.
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You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object
Integrating the velocity equation, we will see that the position equation is:
Let the velocity of the particle is:
To get the position equation we just need to integrate the above equation:
Then:
Replacing that in our integral we get:
Where C is a constant of integration.
Now we remember that
Then we have:
To find the value of C, we use the fact that f(0) = 0.
C = -1 / 3
Then the position function is:
Integrating the velocity equation, we will see that the position equation is:
To learn more about motion equations, refer to:
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Answer:
<em>113.4 J</em>
Explanation:
<u>Elastic Potential Energy</u>
Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.
The spring has a natural length of 0.7 m and a spring constant of k=70 N/m. When the spring is stretched to a length of 2.5 m, the change of length is
Δx = 2.5 m - 0.7 m = 1.8 m
The energy stored in the spring is:
PE = 113.4 J