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olga2289 [7]
3 years ago
10

A 64.0 cm long cord is vibrating in such a manner that it forms a standing wave with two antinodes. (The cord is fixed at both e

nds.) Which harmonic does this wave represent
Physics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

the wave represents the second harmonic.

Explanation:

Given;

length of the cord, L = 64 cm

The first harmonic of a cord fixed at both ends is given as;

f_o = \frac{V}{2L}

The wavelength of a standing wave with two antinodes is calculated as follows;

L = N---> A -----> N    +   N ----> A -----> N

Where;

N is node

A is antinode

L = N---> A -----> N    +   N ----> A -----> N =  λ/2  + λ/2

L = λ

The harmonic is calculated as;

f = \frac{V}{\lambda} \\\\f = \frac{V}{L} = 2(\frac{V}{2L} ) = 2(f_o) = 2^{nd} \ harmonic

Therefore, the wave represents the second harmonic.

L = λ

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Georgia [21]

Answer:

Explanation:

This is basically asking you what the definition of Normal force is. Normal force is the force that pushes back against the weight of something that is sitting (or standing or lying) perpendicular to it. That's why, when you stand on a floor you don't crash through the floor OR go shooting up into space. The Normal force is equal but opposite to your weight. The floor exerts the normal force (pushing up and is positive) while your weight is opposing it (pushing down and is negative.)  Perpendicular is the key word here, I believe.

8 0
3 years ago
Use differentials to estimate the amount of tin in a closed tin can with diameter 3 inch and height 4 inch, if the top and botto
Aloiza [94]

Answer:

dv = 1.03 inch^3

Explanation:

given data:

diameter = 3 inch

radius = 1.5 inch

height 4 inch

top and bottom thickness is 0.02 inch

side thickness = 0.015 inch

we know that volume of the cylinder is given as

v  =\pi r^2 h

by definition of differential we have

dv =\frac{\partial v}{\partial r} dr + \frac{\partial v}{\partial h} dh

where dh = -(0.02  + 0.02) = 0.04 inch    [ sum of top and bottom thickness]

the radius is decreased by 0.02 inch, dr = 0.02 inc,

\frac{\partial v}{\partial r}  = 2\pi r h = 37.69

\frac{\partial v}{\partial h} = \pi r^2 = 7.06

dv = 37.69*(0.02) + 7.06*(0.04)

dv = 1.03 inch^3

3 0
3 years ago
A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 – and lands at bottom of the
Marrrta [24]

Question:

A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 and lands at bottom of the stairs. The staircase has a horizontal length of 8.00 m. We can ignore air resistance. What is the skater's vertical displacement during the jump?

Answer:

y = 1.48 m

Explanation:

Projectile motion is a two dimensional motion experienced by an object or particle that is subjected near the Earth's surface and moves along a curved path under the influence of gravity only. The path followed by projectile motion is called projectile path.

As the skateboarder followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

Also Skateboard jumps horizontally, So initial velocity has only horizontal component.

Horizontal component of initial velocity = v_{i_{x}} = 14.5 m/s

Horizontal displacement = x = 8.00 m

Vertical displacement = y = ?

Using the following formula

x = v_{i_{x}}t

8 = (14.5)(t)

t = 0.55 s

As skateboarder jumps horizontally, So there is no vertical component of velocity.

According to 2nd equation of motion

y = v_{i_{y}}t + \frac{1}{2}gt^{2}

As v_{i_{y}} = 0

So

y = 0.5gt²

y = 0.5*9.8*(0.55)²

y = 1.48 m

8 0
3 years ago
Read 2 more answers
36. What is the current of the circuit in the picture to the right?
joja [24]

Answer:

D. 0.6 Watts

Explanation:

Hopes this help sorry if am wrong. (0;)

7 0
2 years ago
Read 2 more answers
You work for the city water department and need to pump 3400 liters/minute of water from a tank at ground level into a vented (i
umka21 [38]

Answer:

P_E=46.2778\ kW

v=1.804\ m.s^{-1}

Explanation:

Given:

  • flow rate of water, \dot{V}=3400\ L.min^{-1}=3.4\ m^3.min^{-1}

<em>∵Density of water is 1 kg per liter</em>

∴mass flow rate of water, \dot{m}=3400\ kg.min^{-1}

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<u>Now the power required for pumping the water at given conditions:</u>

P=\dot{m}.g.h

P=\frac{3400}{60} \times 9.8\times 75

P=41650\ W

<u>Hence the electric power required:</u>

P_E \times \eta=P

P_E \times 0.9=41650

P_E=46.2778\ kW

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v=\dot{V}\div a

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