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2 years ago

A flight into space by a spacecraft where the spacecraft returns to Earth without achieving orbit is called a

Physics

1 answer:

Gwar [14]2 years ago

4 0

b. par orbital flight

may be .

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2. A ball is released from a vertical height of 20 cm. It rolls down a "perfectly

Paraphin [41]

Answer:

20 cm

Explanation:

Given that a ball is released from a vertical height of 20 cm. It rolls down a "perfectly frictionless" ramp and up a similar ramp. What vertical height on the second ramp will the ball reach before it starts to roll back down?

Since it is perfectly frictionless, the Kinetic energy in which the ball is rolling will be equal to the potential energy at the edge of the ramp.

Therefore, the ball will reach 20 cm before it starts to roll back down.

7 0

3 years ago

. A 13-g goldfinch has a speed of 8.5 m/s. What is its kinetic energy?

lesya692 [45]

PLEASE PRESS THE “Thanks!” BUTTON! :)
13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J

3 0

2 years ago

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie

leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

$MV=mv$

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

$V = \frac{mv}{M}$

Also we have that $m/M = 1/7 times$

On the other hand we have from law of conservation of energy that

$W_f = KE$

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

$F_f*S = \frac{1}{2}MV^2$

$\mu M*g*S = \frac{1}{2}MV^2$

$\mu g*S = \frac{1}{2}( \frac{mv}{M})^2$

$\mu = \frac{1}{2} (\frac{1}{7}v)^2$

$\mu = \frac{1}{98}v^2$

$\mu = \frac{1}{g(98)(5.1)}v^2$

Here we can apply the law of conservation of energy for light mass, then

$\mu mgs = \frac{1}{2} mv^2$

Replacing the value of $\mu$

$\frac{1}{g(98)(5.1)}v^2 mgs = \frac{1}{2}mv^2$

Deleting constants,

$s= \frac{(98*5.1)}{2}$

$s = 249.9m$

7 0

3 years ago

How do you ask someone out?

vazorg [7]

talk, make conversation. text isnt always the answer, but sadly now it is. text them or better yet, call them. you can talk and then do not just blurt it out. say it calmly. they say yes, congrats, but if they say no, do not have a mental breakdown. it might ruin a friendship.

4 0

3 years ago

Read 2 more answers

How does a sound wave's amplitude affect the sound we hear? How does a sound

damaskus [11]

Answer:

cause we hear differently

Explanation:

7 0

3 years ago

Read 2 more answers