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kow [346]
2 years ago
7

A conductor is formed into a loop that encloses an area of 1.0 m2. The loop is orientedat a 30.0° angle with the xy-plane. A var

ying magnetic field is oriented parallel to thez-axis. If the maximum emf induced in the loop is 25.0 V, what is the maximum rate atwhich the magnetic field strength is changing
Physics
1 answer:
ivolga24 [154]2 years ago
3 0

Answer:

29 T/s

Explanation:

Given:

Area enclosed by loop, A = 1 m²

Maximum induced emf, e = 25.0 V

loop is oriented at an angle 30° with the x-y plane.

varying magnetic field is oriented parallel to z-axis.

we have to find \frac{dB}{dt}_{max}

Induced emf is given by:

e =-A.cos\theta .\frac{dB}{dt}\\ \Rightarrow \frac{dB}{dt}=-\frac{e}{Acos\theta} = -\frac{25}{1\times cos30^o} = -28.86T/s≈29T/s

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Is it possible for two different atoms of carbon to have different numbers of neutrons in their nuclei? Explain.
bezimeni [28]

Answer:

Yes , it is possible  for two different atoms of carbon to have different numbers of neutrons in their nuclei .

Explanation:

Isotopes -

Atoms of the element with same number of the electrons and protons , but differ in the number of neutrons , are called as the isotopes .

The isotopes of the element have the same number of protons and electrons , hence have the same chemical and physical properties .

Many isotopes occurs naturally .

In case of Carbon ,  

Carbon too have isotopes ,  

i.e.  

Carbon - 13 and Carbon - 14

carbon - 13 , have seven neutrons  

Carbon - 14 , have eight neutrons .

4 0
3 years ago
A small apple weighs 0.8N. How much would an apple that is 4 times as massive weigh?
-BARSIC- [3]

Answer:

W=31.99 N

Explanation:

W= 8 N (N= kg*m/ s^2)

W= m* g

8 N= m * 9.8 m/s^2

m= 0.816 kg

m*4= (0.816)4

= 3.264 kg

W= mg

= (3.264 kg)(9.8 m/s^2)

W=31.99 N

4 0
3 years ago
A block has a volume of 0.09 m3 and a density of 4,000 kg/m3. What's the force of gravity acting on the block in water?
12345 [234]

                                       Density = (mass) / (volume)

                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
by  0.09 m³ :           (4,000 kg/m³) x (0.09 m³) = mass

                                 mass = 360 kg .

Force of gravity = (mass) x (acceleration of gravity)

                           = (360 kg) x (9.8 m/s²)

                           = (360 x 9.8)  kg-m/s²

                           =   3,528 newtons . 

That's the force of gravity on this block, and it doesn't matter
what else is around it.  It could be in a box on the shelf or at
the bottom of a swimming pool . . . it's weight is 3,528 newtons
(about 793.7 pounds).

Now, it won't seem that heavy when it's in the water, because
there's another force acting on it in the upward direction, against
gravity.  That's the buoyant force due to the displaced water.

The block is displacing 0.09 m³ of water.  Water has 1,000 kg of
mass in a m³, so the block displaces 90 kg of water.  The weight
of that water is  (90) x (9.8) = 882 newtons (about 198.4 pounds),
and that force tries to hold the block up, against gravity.

So while it's in the water, the block seems to weigh

       (3,528  -  882) = 2,646 newtons  (about 595.2 pounds) .

But again ... it's not correct to call that the "force of gravity acting
on the block in water".  The force of gravity doesn't change, but
there's another force, working against gravity, in the water.
5 0
3 years ago
Read 2 more answers
Find the coefficient of kinetic friction μk. express your answer in terms of some or all of the variables d1, d2, and θ.
Andre45 [30]
<span>internet tension = mass * acceleration internet tension = 23 – Friction tension = 14 * acceleration Friction tension = µ * 14 * 9.8 = µ * 137.2 23 – µ * 137.2 = 14 * acceleration Distance = undemanding speed * time undemanding speed = ½ * (preliminary speed + very final speed) Distance = ½ * (preliminary speed + very final speed) * time Distance = 8.a million m, preliminary speed = 0 m/s, very final speed = a million.8 m/s 8.a million = ½ * (0 + a million.8) * t Time = 8.a million ÷ 0.9 = 9 seconds Acceleration = (very final speed – preliminary speed) ÷ time Acceleration = (a million.8 – 0) ÷ 9 = 0.2 m/s^2 23 – µ * 137.2 = 14 * 0.2 resolve for µ</span>
6 0
3 years ago
Read 2 more answers
A motorcycle moving 18.8 m/s has<br> 57800 J of KE. What is its mass?
Brums [2.3K]

Answer:

m = 327.07 kg

Explanation:

Given that,

Kinetic energy of a motorcycle, E = 57800 J

Velocity of the motorcycle, v = 18.8 m/s

We need to find the mass of the motorcycle. The kinetic energy of an object is given by :

E=\dfrac{1}{2}mv^2

m is mass

m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg

So, the mass of the motorcycle is 327.07 kg.

8 0
2 years ago
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