Which expression is equivalent to the given expression? 17x−32x x(17−32) x(32−17) 17x(1−32) 17(x−32)

Lila collected the honey from 3 of her beehives. From the first hive she collected 2/3 gallon of honey. The last two hives yield

slamgirl [31]

Answer:

a). Lila collected 7/6 gallon in all.

b). She used for baking 5/12 gallon.

c) was left 1/3 gallon of honey

D) She used 3/8lb flour to make the brownies.

Step-by-step explanation:

a). Lila collected 7/6 gallon in all.

$\frac{2}{3} +\frac{1}{4} +\frac{1}{4} \\$

LCM=3*4=12

$\frac{8+3+3}{12}=14/12=7/6$

b). She used for baking 5/12 gallon.

She had 7/6 gallon of honey. She used 3/4 gallon for baking. To know how much honey was left, you have to substract 3/4 gallon from the total available honey 7/6 gallon.

$\frac{7}{6}-\frac{3}{4}$

You need to find LCM to substract fractions with different denominator:

LCM=12

$\frac{14-9}{12}=\frac{5}{12}$

c) was left 1/3 gallon of honey

To know how much honey was left you need to substract from the initial quantity of honey that is 3/4 gallon, the quantities used for baking, that are 1/6 gallon and 1/4 gallon.

Less common multiple: 12

$\frac{3}{4}-\frac{1}{6} -\frac{1}{4}$

We use LCM 12 to substract:

$\frac{9-2-3}{12}=\frac{4}{12} =\frac{1}{3}$

D) She used 3/8lb flour to make the brownies.

You know she used 1/2 lb flour to make the bread and to make cookies 1/8 more. So you need to do following math:

d) $\frac{1}{2} +\frac{1}{8} =\frac{4+1}{8} =\frac{5}{8}$

She used 5/8 to make cookies and she used 1/4 more to make cookies than brownies, then you have to do following math;

$\frac{5}{8}-\frac{1}{4}=\frac{5-2}{8}=\frac{3}{8}$

5 0

3 years ago

A pipe is 10 ft long. It need to be cut into pieces that are each 2/5 feet long. How many pieces can be made from the pipe?

e-lub [12.9K]

The answer is 25. To check 10/.4 is 25 and 0.4 equals to 2/5

3 0

3 years ago

Please guys help me out with this

Kisachek [45]

When you have a negative exponent, you move the variable with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

$x^{-2}$ or $\frac{x^{-2}}{1} =\frac{1}{x^2}$

$\frac{1}{2y^{-3}} =\frac{y^3}{2}$ (you don't move the "2" because "2" has an exponent of 1, only "y" has the negative exponent)

$\frac{5^{-2}}{y}=\frac{1}{(5^2)y} =\frac{1}{25y}$

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (But you can only combine the exponents when the variables are the same)

$x^2(y^3)=x^2y^3$ (You can't combine them because they have different variables of x and y)

$x^3(x^5)=x^{(3+5)}=x^8$

$y^3(y^2)=y^{(3+2)}=y^5$

There's two ways you can do this. Either by first making all the exponents positive then do subtraction, or multiply them then make all the exponents positive. I'm doing the 2nd way.

$2w^7u^{-2}w^{-6}*9y^{-6}*2y^9u$ You can combine the numbers 2 x 9 x 2 = 36

$36w^7u^{-2}w^{-6}y^{-6}y^9u$ Now multiply the terms with the same variables

$36(w^{7+(-6)})(u^{(-2+1)})(y^{(-6+9)})$

$36(w^1)(u^{-1})(y^3)$ Now make all the exponents positive

$\frac{36wy^3}{u}$

If you were to do subtraction, here is what you need to know:

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents together. (Reminder: they have to be the same variable in order to combine the exponents)

For example:

$\frac{x^3}{x^2} =x^{(3-2)}=x^1$ or x