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Sergeu [11.5K]
3 years ago
10

Which expression is equivalent to the given expression? 17x−32x x(17−32) x(32−17) 17x(1−32) 17(x−32)

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
Answer would be x(17-32)
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30 seconds of 2.5 mins in percentage
WARRIOR [948]

Answer:

20%

Step-by-step explanation:

2.5 min =(60×2.5)sec=150 sec

30sec to 150sec=30×100/150=20%

7 0
3 years ago
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The table shows a pattern of exponents.<br><br> What is the pattern as the exponents decrease?
Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0
3 years ago
Read 2 more answers
At a college, 4/5 of the students take an English class. Of these students, 5/6 Composition. Which fraction of the students at t
Alchen [17]
If I’m doing it correctly it’s 2/3 but I haven’t done it in a while
3 0
3 years ago
Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither
Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

7 0
3 years ago
K- 3/10 = 2/5 <br> What does k equal
Vesna [10]

Answer:

k = 7/10

or as a decimal is 0.7

3 0
3 years ago
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