Question

A cyclist maintains a constant velocity of 4.1 m/s headed away from point A. At some initial time, the cyclist is 244 m from point A. What will be his displacement from his starting position after 60 s?

Answer 1

Answer:

$d=490\ m$ is his final displacement from the point A after 60 seconds.

Explanation:

Given:

Cyclist is moving away from A.

• velocity of cyclist, $v=4.1\ m.s^{-1}$

• displacement of the cyclist from point A at the time of observation, $d_i=244\ m$

• time after which the next observation is to be recorded, $t=60\ s$

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

$\Delta d=v.t$

$\Delta d = 4.1 \times 60$

$\Delta d=246\ m$

Now the the final displacement from point A after the mentioned time:

$d=d_i+\Delta d$

$d=244+246$

$d=490\ m$