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aev [14]
3 years ago
8

A cyclist maintains a constant velocity of 4.1 m/s headed away from point A. At some initial time, the cyclist is 244 m from poi

nt A. What will be his displacement from his starting position after 60 s?
Physics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

d=490\ m is his final displacement from the point A after 60 seconds.

Explanation:

Given:

Cyclist is moving away from A.

  • velocity of cyclist, v=4.1\ m.s^{-1}
  • displacement of the cyclist from point A at the time of observation, d_i=244\ m
  • time after which the next observation is to be recorded, t=60\ s

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

\Delta d=v.t

\Delta d = 4.1 \times 60

\Delta d=246\ m

<u>Now the the final displacement from point A after the mentioned time:</u>

d=d_i+\Delta d

d=244+246

d=490\ m

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