If a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.
<u>Explanation:</u>
Relative permittivity of a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.
It is given by the expression
k=k=ε /ε0
where ε denotes absolute permittivity and ε0 denotes permittivity of vacuuum.
Absolute permittivity ε of vacuum= ε0
therefore k= ε0/ ε0=1
dielectric constant of vacuum is 1 .
Heat will always flow from High temperature to low temperature
here we know that the temperature inside the room is 60 degree while out side temperature is 80 degree
so the flow of heat is from outside to inside the room as heat flow is always from higher temperature to lower temperature
So after some time due to heat flow from outside the temperature of room will increase
And after long time the temperature of room and outside will be same and heat transfer will become in equilibrium
Answer:
L = 0.99 m = 99 cm
Explanation:
The period is the reciprocal of the frequency.
T = 1/0.5 = 2.0 s
T = 2π√(L/g)
L = g(T/2π)²
L = 9.8(2.0/2π)² = 0.99 m
If the system accelerates upward, it will cause the apparent gravity to increase. This will require a longer pendulum to keep the same period, or shorten the period if the length remains the same. This shows up in the equation where the product of gravity and the square of the period must remain constant for the length to remain constant.
the equation of the tangent line must be passed on a point A (a,b) and
perpendicular to the radius of the circle. <span>
I will take an example for a clear explanation:
let x² + y² = 4 is the equation of the circle,
its center is C(0,0). And we assume that the tangent line passes to the point
A(2.3).
</span>since the tangent passes to the A(2,3), the line must be perpendicular to the radius of the circle.
<span>Let's find the equation of the line parallel to the radius.</span>
<span>The line passes to the A(2,3) and C (0,0). y= ax+b is the standard form of the equation. AC(-2, -3) is a vector parallel to CM(x, y).</span>
det(AC, CM)= -2y +3x =0, is the equation of the line // to the radius.
let's find the equation of the line perpendicular to this previous line.
let M a point which lies on the line. so MA.AC=0 (scalar product),
it is (2-x, 3-y) . (-2, -3)= -4+4x + -9+3y=4x +3y -13=0 is the equation of tangent