How do you write 2x in radical form

2 answers:

8 0

The correct answer is
#2x^(-1/2)

8 0

$\sqrt{2x}=2x^{\frac{1}{2}}$

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krek1111 [17]

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2x-4y=-16
ax+4y=6 +
--------------------
2x+ax=-10; for x=-2,
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3

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