Answer:
The loan was for 9 months only
Step-by-step explanation:
In this question, we are concerned with calculating the time taken for a loan om an interest to be paid back
To calculate this, we use the simple interest formula
Mathematically;
I = PRT/100
where P is the principal which is the amount borrowed and that is $500 according to the question
R is the rate which is 8% according to the question
Interest can be calculated by subtracting the principal from the amount paid back = 530-500 = 30$
We now plug these values into the equation
30 = (500 × 8× T)/100
100 × 30 = 4000T
T = 3000/4000
T = 0.75 (same as 0.75 × 12 months = 9 months)
Answer:
Kindly check explanation
Step-by-step explanation:
The following mistakes could be explained observed from the plotted bar chart presented in the attachment :
1.) The numeric label of the y-axis which shows the number of text messages isn't well scaled, the numbering did not start from 0, hence this is a defect in the scaling of the bar chart.
2.) Looking closely, the plotted bars do not ALIGN well in terms of spacing as the interval between each bar isn't consistent.
3.) Both the x and y axis of the graph are t labeled thus failing to add a good and meaningful description to the plot especially for first time viewers.
Answer:
none lul
Step-by-step explanation:
my noggin
Answer:
<h2>3 weeks</h2>
Step-by-step explanation:
Step one:
given data
expected amount =$200
cash already at hand=$80
savings per week=$40
let the number of weeks be x
Step two:
the linear function for the situation is the same as the equation of a straight line
y=mx+c------1
200=4x+80
solve for x
200-80=40x
120=40x
divide both sides by 4
x=120/40
x= 3 weeks
<u>Chandler will save for 3 weeks</u>
Answer:
r equals StartFraction C Over 2 pi EndFraction
Step-by-step explanation:
we know that
The circumference of a circle is equal to
where
r is the radius of the circle
Solve for r
That means -----> isolate the variable r
Divide by 2π both sides
Simplify right side
Rewrite
so
r equals StartFraction C Over 2 pi EndFraction
