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pentagon [3]
2 years ago
6

Two ocean beaches are being affected by erosion. The table shows the width, in feet, of each beach measured at high tide where 1

995 is represented by year 0:
Question 1a. Describe the patterns shown by the erosion data measurements shown for each of the beaches in the table.
Question 1b. Between which years will the beaches have approximately the same width?
Question 1c. Assuming these rates remain constant, what can you do to get a better approximation of when the two beaches will have the same width?

Mathematics
1 answer:
Verizon [17]2 years ago
3 0

A= 1.142 m/hr

Width of beach at 8 p.m. = 36 m

Width of beach at 3 a.m. = (36-8) m =28 m

Average change in width(A) = change in width (Width of beach at 8 p.m.-Width of beach at 3 a.m.0/ time in hours

A= ( 36-28)/ 7

A= 8/7 m/hr

A = 1.142 m /hr

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3 years ago
Solve this system of equations.
nata0808 [166]

x = 8, y = 0

y=\frac{1}{2}x-4

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We substitute y=\frac{1}{2}x-4 into the y for y=-\frac{1}{4}x+2, and we get:

\frac{1}{2}x-4 = -\frac{1}{4}x+2

+\frac{1}{4}x   +\frac{1}{4}x

\frac{3}{4}x -4 = 2

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The 4's cross out and we get:

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Not we substitute x(8) into one of our original equations: y=\frac{1}{2}x-4

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y-0

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Hope that helps!

3 0
2 years ago
Read 2 more answers
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