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tia_tia [17]
3 years ago
5

Name an element which matches the description

Chemistry
1 answer:
ikadub [295]3 years ago
6 0

1) Uranium

2) Carbon in the form of graphite

3) Palladium

Explanation:

1) In the nuclear reactor the fuel is represented by some uranium isotopes which are easily fissionable.

2) Graphite is made from carbon sheets in which there are free electrons that are moving freely so the carbon, in this form, is able to conduct electricity.

3) Commonly inert electrodes are made from platinum (Pt) or gold (Au) metals, because of the propriety of this metals to not interact chemically very easily with various substances.

Learn more:

uranium isotopes

brainly.com/question/9099776

graphite

brainly.com/question/8853712

inert electrodes

brainly.com/question/9822656

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Why natural fas is not used as a bottled gas or as a motor fuel?
qaws [65]

Answer:

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7 0
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3 years ago
Read 2 more answers
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
In order to rinse the system of exhaled C02 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flo
LuckyWell [14K]

Answer:

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Explanation:

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