Whats the complete chemical symbol for the ion that has : 13 neutrons 11 protons , and 9 electrons.

What happens when Potassium Hydroxide reacts with Sulphuric Acid?

Ede4ka [16]

As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.

When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.

As a result of neutralization reaction, Potassium Sulphate and Water is formed.

2KOH + H2SO4 ----> K2SO4 + 2H2O

Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.

5 0

3 years ago

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An internal combustion engine relies primarily on the efficient production of energy by the combination of oxygen (02) and gasol

jeka57 [31]

Answer is: <span>the exact ratio of oxygen to octane for is 12.5 : 1.
</span>Balanced chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O or multiply by 2:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O.
There same number of atoms on both side of balanced chemical reaction: eight carbon atoms, eighteen hydrogen atoms and twenty five oxygen atoms.

7 0

3 years ago

The layering of eroded sediments is called:

Aleks [24]

4. the rock cycle is the layering of eroded sediments

6 0

3 years ago

In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

m_a_m_a [10]

Correct answer -->filtration

8 0

4 years ago

"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum

UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = $25^{o} C$

= (25 + 273) K

= 298.15 K

Osmotic pressure = 531 mm Hg or 0.698 atm (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

0.698 = $C \times 0.082 \times 298.15 K
$

C = 0.0285

This also means that,

$\frac{\text{moles}}{\text{volume (in L)}}$ = 0.0285

So, moles = 0.0285 × volume (in L)

= 0.0285 × 0.100

= $2.85 \times 10^{-3
}$

Now, let us assume that mass of $C_{12}H_{23}O_{5}N$ = x grams

And, mass of $C_{12}H{22}O_{11}$ = (1.00 - x)

So, moles of $C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}$

= $\frac{x}{369}$

Now, moles of $C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}$

= $\frac{x}{369} + \frac{(1.00 - x)}{342}$

= $2.85 \times 10^{-3}$

= x = 0.346

Therefore, we can conclude that amount of $C_{12}H_{23}O_{5}N$ present is 0.346 g and amount of $C_{12}H_{22}O_{11}$ present is (1 - 0.346) g = 0.654 g.

4 0

3 years ago