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KatRina [158]
3 years ago
6

Find m …………….. ………….. …………..

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0

Answer:

Hope this helps I'm not sure if its correct though, it must be correct anyway. So yea.

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Which statement is not true? X squared equals 100 if and only if X equals 10 orX equals -10. If X squared equal 100 then X equal
mamaluj [8]

Answer:

the second statement is not true

Step-by-step explanation:

If x squared equals 100, it doesn't mean necessarily that x is positive ten, since you can get 100 also by squaring the value (-10):

(-10)(-10)^{2} = (-10) x (-10) = 100

The second statement is ignoring the possibility of x being a negative ten which also gives 100 as answered when squared.

7 0
3 years ago
Need help with a math question
Mekhanik [1.2K]

Answer:

z =3\sqrt{13}

Step-by-step explanation:

In the figure you can identify up to 3 straight triangles.

To solve the problem, write the Pythagorean theorem for each triangle.

<em>Triangle 1</em>

13^2 = z^2 + x^2

<em>Triangle 2</em>

z^2 = y^2 + 9^2

<em>Triangle 3</em>

x^2 = y^2 + 4^2

Now substitute equation 2 and equation 3 in equation 1 and solve for y.

13^2 = y^2 + 9^2 + y^2 + 4^2

13^2 = 2y^2 + 9^2 + 4^2

169 = 2y^2 + 81 + 16

2y^2 =72

y^2 =36

y =6

substitute the value of y in the second equation and solve for z

z^2 = 6^2 + 9^2

z^2 = 36 + 81

z^2 = 117

z = \sqrt{117}

z =3\sqrt{13}

5 0
3 years ago
If I have 25 cookies and 100 friends how many pieces would each friend get if I eat 3 cookies (please put in fractions)
Svet_ta [14]

Answer:

they would each get 1/4 of a cookie

Step-by-step explanation:

7 0
3 years ago
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Jennifer is a lifeguard at the same pool. She earns $137.25 for 15 hours of lifeguarding how much does Jennifer earn per hour?
Ainat [17]
Jennifer only earns $9.15 per hour.
6 0
4 years ago
A school is planning an event to raise $1,000 for charity. The cost of organizing the event is $200. The tickets are priced at $
givi [52]
<span>if they already have 200 then the "must collect" 800 to reach 1000</span>
7 0
4 years ago
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