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3 years ago

Y = (x + 3)^2 -4 and identify the axis of symmetry

Mathematics

1 answer:

Vikki [24]3 years ago

7 0

Answer:

Step-by-step explanation:

the line for equation : x = - 3

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Which container could logically have a capacity of 1,000 liters ? A kitchen sink B bathtub C measuring cup D Hot tub

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If it makes it any easier, when you see "a thousand liters," think of 260 gallons of milk. Which do you think could it fill up without going over?

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2 years ago

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During the first 14 days 2744 people visited a new store. The same number of people visited the store each day. About how many p

Vikentia [17]

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2 years ago

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Write an equation for the nth term of the arithmetic sequence 22, 15, 8, 1,.

DaniilM [7]

Answer:

aₙ = 7n +29

Step-by-step explanation:

Arithmetic sequence

22 ; 15 ; 8; 1;........aₙ

the nth term

aₙ = -7n +29

8 0

2 years ago

Sally went school shopping she had a budget of 10.00 she bought a pen for 1.75 and a paper for 1.33 her change was 6.08 how much

irakobra [83]

Answer:

$0.84

Step-by-step explanation:

1. find total cost of both the pen and paper

$1.75 + $1.33 = $3.08

2. find the amount Sally spent

$10 - $6.08 = $3.92

3. find cost of ruler

$3.92 - $3.08 = $0.84

4 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

2 years ago