Answer:
d . ................. .........
The smaller surface area
Hope this helps!
Calorimeter is an instrument which is used for measurement of heat liberation or absorption from a system during the flow of energy.
Answer: Option A
<u>Explanation:</u>
When the heat is liberated from the system, during the flow of energy it undergoes a exothermic reaction. Similarly, when the heat is absorbed by the system during the flow of energy, the system undergoes an endothermic reaction.
The calorimeter as the name suggest is the meter to calibrate calorie. Calorie here refers to the heat energy, which is being calibrated or measured during the flow of energy, either liberated from the system or being absorbed by the system.
Answer:
Proof in explanation.
Explanation:
Consider a thin cylinder, whose thickness to diameter ration is less than 1/20, the hoop stress can be derived as follows:
Let,
L = length of cylinder
d = internal diameter of cylinder
t = thickness of wall of cylinder
P = internal pressure
σH = Hoop Stress
σL = Longitudinal Stress
Total force on half-cylinder owing to internal pressure = P x Projected Area = P x dL (Refer fig 9.1)
Total resisting force owing to hoop stress setup in walls = 2 σH L t
Therefore,
P d L = 2 σH L t
σH = Pd/2t _____________ eqn (1)
Now, for longitudinal stress:
Total force on end of cylinder owing to internal pressure = P x Projected Area = P x πd²/4
Area resisting this force = π d t (Refer fig 9.2)
Longitudinal Stress = Force/Area
σL = (Pπd²/4)/(πdt)
σL = Pd/4t ____________ eqn (2)
Dividing eqn (1) by eqn (2)
σH/σL = 2
<u>σH = 2 σL</u> (Hence, Proved)
Answer:
a) v1 = 33.9 m/s
, v2 = 39.6 m/s, b) a = 1015.4 m/s² and c) a = 1742.4 m/s²
Explanation:
To solve this exercise we will use the relationship between angular and linear quantities
a) The angular and linear velocity are related by
v = w r
Let's reduce the quantities to the SI system
w1 = 9.00 rev / s (2π rad / 1rev) = 18 π rad / s = 56.55 rad / s
w2 = 7.00 rev / s = 14π rad / s = 43.98vrad / s
v1 = 56.55 0.6
v1 = 33.9 m / s
v2 = 43.98 0.9
v2 = 39.6 m / s
b) centripetal acceleration for v1
a = v² / r
a = 33.9² / 0.6
a = 1015.4 m / s²
c) centripetal acceleration for v2
a = 39.6² / 0.9
a = 1742.4 m / s²
