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julia-pushkina [17]

3 years ago

5

Why does a ship need an anchor

2 answers:

egoroff_w [7]3 years ago

6 0

A ship needs an anchor because if a ship stop its just going to float around the ocean, but if the ship has the anchor then the ship will stay in place.

Len [333]3 years ago

5 0

So there is extra wait that pulls the boat to stop.

Can i get brainliest I need it

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A student claims that any object in motion must experience a force that keeps it in motion. Do you agree or disagree? Explain yo

frosja888 [35]

Answer:

I disagree

Explanation:

I think the students claim is wrong because according to Newton's First Law an object that is in motion stays in motion unless acted upon by an unbalanced force. Which makes the students claim wrong because a object doesn't require another force to keep it moving.

5 0

3 years ago

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What do submarines translate into pictures?

prohojiy [21]

It lets the viewer know it's something to do with underwater.

6 0

3 years ago

Two masses —m1 and m2— are connected by light cables to the perimeters of two cylinders of radii r1 and r2 respectively, as show

Aleksandr [31]

Answer:

Part a)

Mass of m2 is given as

$m_2 = \frac{20}{3} kg$

Part b)

Angular acceleration is given as

$\alpha = 1.96 rad/s^2$

Part c)

Tension in the rope is given as

$T = 176.6 N$

Explanation:

Part a)

When m1 and m2 both connected to the cylinder then the system is at rest

so we can use torque balance here

$m_1g r_1 = m_2 g r_2$

$20 g(0.5) = m_2 g(1.5)$

$10 = 1.5 m_2$

$m_2 = \frac{20}{3} kg$

Part b)

When block m_2 is removed then system becomes unstable

so force equation of mass m1

$m_1g - T = m_1 a$

also we have

$T r_1 = I\alpha$

now we have

$m_1g = \frac{I a}{r_1^2} + m_1 a$

$a = \frac{m_1g}{\frac{I}{r_1^2} + m_1}$

$a = \frac{20 (9.81)}{\frac{45}{0.5^2} + 20}$

$a = 0.981 m/s^2$

so angular acceleration is given as

$\alpha = \frac{a}{r_1}$

$\alpha = \frac{0.981}{0.5}$

$\alpha = 1.96 rad/s^2$

Part c)

Tension in the rope is given as

$T = \frac{I\alpha}{r_1}$

$T = \frac{45 (1.96)}{0.5}$

$T = 176.6 N$

7 0

3 years ago

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.

aivan3 [116]

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

8 0

2 years ago

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What will happen if you drop a golf ball, a baseball, and a bowling ball at the same instant from the top of a tall building

V125BC [204]

Depending on the height of the building they can break due to impact on the floor.

8 0

2 years ago