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Ede4ka [16]
3 years ago
12

From a set of graphed data the slope of the best fit line is found to be 1.35 m/s and the slope of the worst fit line is 1.29m/s

. Determine the uncertainty for the slope of the line.
Physics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Solution:

Let the slope of the best fit line be represented by 'm_{best}'

and the slope of the worst fit line be represented by 'm_{worst}'

Given that:

m_{best} = 1.35 m/s

m_{worst} = 1.29 m/s

Then the uncertainity in the slope of the line is given by the formula:

\Delta m = \frac{m_{best}-m_{worst}}{2}               (1)

Substituting values in eqn (1), we get

\Delta m = \frac{1.35 - 1.29}{2} = 0.03 m/s

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A stone whirled at the end of the a rope 30cm long, makes 10 complete resolution in 2 seconds Find: A. The angular velocity in r
lord [1]

Answers:

A: Angular velocity \omega=31.40 \frac{r a d}{s}

B: Linear velocity v=9.42 \frac{m}{s}

C: Linear Distance d=47.1 \mathrm{m}

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Radius of the rope r=30cm=0.3m

Angular distance\Delta \theta=10 revolutions

Time taken t=2seconds

To find:

A: Angular velocity in radians

B: Linear speed

C: Distance covered in 5 seconds

<u>Step by Step Explanations:</u>

Solution:

A: Angular velocity in radians;

According to the formula, Angular velocity can be calculated as

Angular Velocity = angular distance/ time

\omega=\Delta \theta / \Delta t

Where \omega=Angular velocity

\Delta \theta=Angular distance=10 revolutions

Changing revolutions to radians multiply with 2 \pi, so that we get

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\Delta t =Change in time

Substitute the known values in the above equation we get

\omega=62.80 / 2  

\omega=31.40 \frac{r a d}{s}

B. Linear speed of the rope;

As per the formula

Linear speed = angular speed × radius

v=\omega \times r  

Where \omega=Angular velocity

v=Linear speed of the rope

r=Radius of the rope

Substitute the known values in the above equation we get

v=31.40 \times 0.30

v=9.42 \frac{m}{s}

C. Dsitance covered in 5 seconds;

Linear distance = linear speed × time

d=v \times t

Where d= Linear distance of the rope

v=Linear speed of the rope

t=Time taken

Substitute the known values in the above equation we get

d=9.42 \times 5

d=47.1 \mathrm{m}

Result:

Thus A: Angular velocity of the rope \omega=31.40 \frac{r a d}{s}

B Linear speed of the rope v=9.42 \frac{m}{s}

C: Distance covered in 5 seconds d=47.1 \mathrm{m}

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© Jenna Gray. The author warrants that the work is the author's own and that Stanford University provided no input other than typesetting and referencing guidelines. The author grants permission to copy, distribute and display this work in unaltered form, with attribution to the author, for noncommercial purposes only. All other rights, including commercial rights, are reserved to the author.

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