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3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Physics

1 answer:

ki77a [65]3 years ago

6 0

Answer:

B) The current of the entire circuit is lowered.

Explanation:

There are two ways in which a resistor can be connected in a circuit;

i) Series: In a series connection, resistors are connected end to end. In this arrangement, the current passing through each resistor is the same while the potential difference across each resistor is different.

ii) Parallel: In a parallel connection, resistors are connected to common junctions. In this arrangement, the potential difference across each resistor is the same while the current across each resistor varies.

In a series circuit, the effective resistance is the algebraic sum of resistance of all the resistors connected in series. Hence, if a large resistor is connected in series, the effective resistance of the circuit is greatly increased.

Since the voltage is given by;

V=IR (Ohm's law)

Where R is the effective resistance

Then;

I = V/R

If R becomes very large due to a large resistance connected in series, then the current of the entire circuit is lowered.

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An upward force of 32.6 N is applied via a string to lift a ball with a mass of 2.8 kg. (a) What is the gravitational force acti

Igoryamba

Answer:

a) Fg = -27.4 N

b) Fnet = 5.2 N

c) a = 1.9 m/s2

Explanation:

There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
So, we can write the following expression for Fg:

$F_{g} = m*g = 2.8 kg*(-9.8m/s2) = -27.4 N (1)$

The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:

$F_{net} = T -F_{g} = 32.6 N - 27.4 N = 5.2 N (2)$

According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression:

$a = \frac{F_{net} }{m} = \frac{5.2N}{2.8kg} = 1.9 m/s2 (3)$

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3 years ago

Which of the following color schemes (specifically in jewel tones) is on-trend for 2020?

stiks02 [169]

Answer:

The answer is B complimentary

Explanation:

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An 1100kg car reached 30m/s in 9s from rest. What force did the engine provide?

malfutka [58]

Answer:

≅3666.67 N

Explanation:

Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,

a = acceleration acquired by the object.

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3 years ago

A heavy-duty shock absorber is compressed 4 cm from its equilibrium position by a mass of 700nbspkg. How much work is required

tia_tia [17]

Answer:

Explanation:

A mass of 700 kg will exert a force of

700 x 9.8

= 6860 N.

Amount of compression x = 4 cm

= 4 x 10⁻² m

Force constant K = force of compression / compression

= 6860 / 4 x 10⁻²

= 1715 x 10² Nm⁻¹.

Let us take compression of r at any moment

Restoring force by spring

= k r

Force required to compress = kr

Let it is compressed by small length dr during which force will remain constant.

Work done

dW = Force x displacement

= -kr -dr

= kr dr

Work done to compress by length d

for it r ranges from 0 to -d

Integrating on both sides

W = $\int\limits^{-4}_0 {kr} \, dr$

= [ kr²/2]₀^-4

= 1/2 kX16X10⁻⁴

= .5 x 1715 x 10² x 16 x 10⁻⁴

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Answer:

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