In the problem, two legs measurement were given such as:
Leg 1 = 12 inches
Leg 2 = 15 inches
We need to solve for the third leg. Since it is a right triangle, we can use Pythagorean theorem in solving the missing leg:
c²=b²+a²
When we assume that the third leg is the "c", we can for the value such as:
c² = 12²+15²
c=19.21
When we assume that the third is either "a" or "b":
15² =a² + 12²
a=9
Then, the possible measurement of the third leg is 9 or 19.21.
The difference between the two possible answer is shown below:
Difference = 19.21 -9 = 10.21
Difference =10.21
Answer: i need help on that too
Step-by-step explanation: i need helpppp
1/8x2 and 4x I had usa test prep
The correct answer is B. 592
Explain
The common pattern Number is
48 - 11 = 37 + 22 = 59 - 33 = 26 + 22 = 48 - 11 = 37
37 + 22 = 59
Add 22
59 - 33 = 26
subtract 33
Answer:
1. S.A. = 4350 cm²
2. S.A. = 864 cm²
3. S.A. = 240 cm²
4. S.A. = 224 m²
5. S.A. = 301.6 in.²
6. S.A. = 6,082.1 cm²
7. S.A. = 923.6 in.²
Step-by-step explanation:
1. Surface area of the rectangular prism = 2(LW + LH + WH)
L = 45 cm
W = 25 cm
H = 15 cm
S.A. = 2(45*25 + 45*15 + 25*15)
S.A. = 4350 m²
2. Surface area of the cube = 6a²
a = 12 cm
S.A. = 6(12²)
S.A. = 864 cm²
3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H
b = 4 cm
h = 6 cm
s1 = 4 cm
s2 = 7 cm
s3 = 7 cm
H = 12 cm
Plug in the values
S.A. = 4*6 + (4 + 7 + 7)*12
S.A. = 24 + (18)*12
S.A. = 24 + 216
S.A. = 240 cm²
4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)
S.A. = (8*8) + 4[(8*10)/2]
S.A. = 64 + 4(40)
S.A. = 64 + 160
S.A. = 224 cm²
5. Surface area of the cone = πrl + πr²
r = 6 in.
l = 10 in.
S.A. = π*6*10 + π*r²
S.A. = 60π + 36π
S.A. = 301.592895
S.A. = 301.6 in.² (nearest tenth)
6. Surface area of the sphere = 4πr²
r = 22 cm
S.A. = 4*π*22²
S.A. = 1,936π
S.A. = 6,082.1 cm² (nearest tenth)
7. Surface area of the cylinder = 2πrh + 2πr²
r = 7 in.
h = 14 in.
S.A. = 2*π*7*14 + 2*π*7²
S.A. = 923.6 in.² (nearest tenth)
