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Gala2k [10]
1 year ago
5

for a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 115 m

in and 135 min? (round your answer to four decimal places.)
Mathematics
1 answer:
Firdavs [7]1 year ago
6 0

The required probability that the sample mean courtship time is between 115 min and 135 min is 0.5269.

We know that probability is defined as the proportion of number of favorable outcomes to the total number of outcomes.

Probability implies plausibility. A piece of math deals with the occasion of a sporadic event. The worth is communicated from zero to one. Likelihood has been acquainted in Maths with foresee how likely occasions are to occur.

The significance of likelihood is essentially the degree to which something is probably going to occur. This is the fundamental likelihood hypothesis, which is likewise utilized in the likelihood dispersion, where you will get familiar with the chance of results for an irregular examination. To track down the likelihood of a solitary occasion to happen, first, we ought to know the complete number of potential results.

We have μ=115min

n=50

P(x₁<X<x₂)=P(z₂< (x₂-μ) /S.D) -P(z₁<(x₂-μ)/S.D)

S.D=√(σ²/ n)

=>S.D=√(115)²/50

=>S.D = √(13225)/50

=>S.D = √264.5

=>S.D = 16.26

P(115<X<135)=P(z₂< (135-115)/16.26)-P(z₁ <(100-115) / 16.26)

=>P((115<X<135)=P(z₂<20/16.26)-P(z₁< -15/16.26)

=>P(115<X<135)=P(z₂<1.23) - P(z₁<-0.922)

From the probability distribution table

P(z₂<1.23)=0.6255

P(z₁<-0.922)=0.0986

P(115<X<135)=0.6255-0.0986

=>P(115<X<135)=0.5269

Hence, required probability is 0.5269

To know more about probability, visit here:

brainly.com/question/11234923

#SPJ4

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The upper-left coordinates on a rectangle are (-5, 6)(−5,6)left parenthesis, minus, 5, comma, 6, right parenthesis, and the uppe
sammy [17]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.

If the coordinates of the top of the triangle (breadth) is  (−5,6) and  (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:

D = √(y₂-y₁)²+(x₂-x₁)²

Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6

D = √(6-6)²+(-2-(-5))²

D = √0²+3²

D = √9

D = 3 units

Breadth = 3 units

Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.

16 = 2(3+L)

16 = 6+2L

16-6 = 2L

2L = 10

L = 10/2

L = 5 units.

<em>Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.</em>

7 0
3 years ago
Which translation for: y = (x+3)^2+4<br><br> If you can't see the picture zoom in.
Savatey [412]

Answer:

The answer is B.

Step-by-step explanation:

The original graph of y = x^2 has a vertex at (0,0)

The formula for graph translations is y = (x-#)^2+#

The number inside the parentheses is a horizontal translation.

So, we are given y = (x-(-3))^2+#

The vertex of the graph moves 3 points left, since the number is negative (-3).

The number at the end of the equation is a vertical translation.

So, we are given y = (x+3)^2+4

The vertex of the graph moves 4 points up, since the number is positive (4).

The new vertex is at (-3,4)

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3 years ago
A hungry elf ate 30 of your muffins. that was 5/8 of all of them! how many are left?
Lilit [14]
There18 muffins left
4 0
3 years ago
A) What is the domain and range of the graph? (Use the equations editor or explain)
riadik2000 [5.3K]

The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

a)

This graph extends from x > -5 to x = 1.

The domain

 -5 < x ≤ 1   ------   (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

 -3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

#SPJ1

8 0
2 years ago
The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per
vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

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4 0
3 years ago
Read 2 more answers
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