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3 years ago

What is the missing numbers in the equivalent fraction 8/10=32/?

Mathematics

2 answers:

zzz [600]3 years ago

8 0

Answer: 40

Step-by-step explanation:

32/8 =4

10*4= 40

sergey [27]3 years ago

4 0

Answer:

Step-by-step explanation:

8/10

32/40

Divide 32/8 and you get 4. Multiply by the first denominator to get the second

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What is the equation that you get when you put together the two<br> equations below?

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Answer:

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Step-by-step explanation:

Given the 2 equations

2x + 5y = 19 → (1)

y = 3x - 3 → (2)

Substitute y = 3x - 3 into (1)

2x + 5(3x - 3) = 19

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Which Equation best represents the line graphed above?<br> Y=-3x-1 Y=-3x+1 Y=3x+1 Y=3x-1

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C. y=3x+1 is the answer.

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At the movie theater child admission is $5.20 and adult admission is $9.90.. On Friday 163 tickets were sold for a total sales o

Jet001 [13]

The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the number of children and y represent the number of adult, hence:

5.2x + 9.9y = 1303.5 (1)

Also:

x + y = 163 (2)

From both equations:

x = 66, y = 97

The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.

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2 years ago

4 A figure is graphed on a coordinate grid as shown.

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Step-by-step explanation:

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3 years ago

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The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

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3 years ago